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mel-nik [20]
2 years ago
8

david has 12 baseball hats. david and his brothers have more than 19 hats combined. how many hats could david’s brothers have?

Mathematics
1 answer:
Elena L [17]2 years ago
6 0

Answer:

Davids brother has more then 7 hats

Step-by-step explanation:

because together they have 19 and david himself has 12. 19-12 equals 7 and the question states that have more then 19 hats together so we know his brother has to have 7 hats but we dont know how many more he has.

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Using the table below, evaluate whether a monkey's age in years is a function of its height in inches.
Ksivusya [100]

Answer:

There is no function since there is no association between all the numbers

Step-by-step explanation:

If you were to put them in a graph they would be every where and make there be no function.

8 0
3 years ago
Paul has a collection of nickels and
VARVARA [1.3K]

Answer:

#nickels = 50

#dimes = 100

Step-by-step explanation:

system of equations:

n + d = 150

.05n + .10d = 12.50

let n = '150 - d' and substitute this into the second equation

.05(150-d) + .10d = 12.5

7.5 - .05d + .10d = 12.5

.05d = 5

d = 5/.05

d = 100

n = 50

4 0
3 years ago
12:8:100 in its simplest form as a ratio.
nikitadnepr [17]

Answer:

3:2:25 is the correct answer

Step-by-step explanation:

hope this helps .

3 0
2 years ago
Read 2 more answers
Which side lengths could be used to form a triangle?
Fynjy0 [20]
The answer is C because it fits the formula a+b=c
2+4=6
8 0
3 years ago
A rectangular piece of land is to be fenced using two kinds of fencing. Two opposite sides will be fenced using standard fencing
damaskus [11]

Answer:

Therefore the dimension of the rectangular piece of land is 375 m by 250 m.

Step-by-step explanation:

Given that,

Two opposite sides of rectangular land will be fenced using standard fencing that costs $6 per m while the other two side will require heavy duty fencing that costs $9 per m.

Let the length and width of the rectangular x and y respectively.

Then total cost for fencing = \$(2x\times 6+2y\times 9)

                                            =$(12x+18y)

Then,

12x+18y= 9,000

⇒ 2x+3y=1,500     [ cancel out common factor 6]

⇒3y= 1500 - 2x

\Rightarrow y=\frac{1500-2x}{3} ....(1)

The area of the rectangular land is = Length × width

                                                          = xy

Let,

A=xy

Putting the value of y

A=x.\frac{1500-2x}{3}

\Rightarrow A=\frac13(1500x-2x^2)

Differentiating with respect to x

A'=\frac13(1500-4x)

Again differentiating with respect to x

A''=-\frac43

Now we have to determine the critical value of A.

For critical value set A'=0

\frac13(1500-4x)=0

⇒1500-4x=0

\Rightarrow x=\frac{1500}{4}

\Rightarrow x=375 m

Since, A''|_{x=375}=-\frac43. at x=375 m the area of the rectangular piece of land is maximum.

From equation (1) we get when x=375

y=\frac{1500-2\times 375}{3}

⇒y=250 m

Therefore the dimension of the rectangular piece of land is 375 m by 250 m.

3 0
3 years ago
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