Explanation:
☆ In the figure above, arc SBT is one quarter of a circle with center R and radius 6. If the length plus the width of rectangle ABCR is 8, then the perimeter of the shaded region is —
ANSWER :–
LET AR = a and RC = b
We know that –
perimeter of quarter circle = ( 2πr ) / 4 = 3π
AND –
AS = 6 - a , CT = 6 - b , AC = RB = 6 ( radius )
➨ perimeter of the shaded region = AS+AC+CT+C(SBT)
➨ Perimeter = ( 6 - a ) + 6 + ( 6 - b ) + 3π
➨ Perimeter = 18 - ( a + b ) + 3π
● length + width = 8 ( given )
➨ Perimeter = 18 - 8 + 3π
Answer:
➨ Perimeter = 10 + 3π
~Kandy~
Hope this helps!
Brainliest Please!
The conclusion that can be drawn about the second punic war from the information in the map is;
D) Rome had enemies both on the Italian peninsula and in North Africa.
<h3>Facts about the Second Punic War</h3>
From the second punic war from the information on the map, we can tell that the Roman Republic were fighting against the Carthaginian empire which was based in Northern region of Africa.
Now, some kingdoms in the Italian peninsula allied themselves with the Carthage empire.
Finally, we can say that Rome had enemies in North Africa (Carthage empire) and on the the kingdoms of the Italian peninsula that allied themselves with the Carthage empire.
In conclusion, the correct answer is that Rome had enemies on the Italian peninsula and in northern Africa.
The missing options are;
A) Rome had established firm control of the Italian peninsula prior to the Second Punic War.
B) The Roman's allies played a key role in their victory on the Italian peninsula.
C) Rome was also at battle with the Carthaginians over territory in the Eastern Mediterranean.
D) Rome had enemies both on the Italian peninsula and in North Africa.
Read more about Second Punic War at; brainly.com/question/2612078
Answer:
TRUE!
The amendment states "...nor shall any person be subject for the same offence to be twice put in jeopardy of life or limb."