Answer:
D. Pythagorean
Step-by-step explanation:
Given the identity
cos²x - sin²x = 2 cos²x - 1.
To show that the identity is true, we need to show that the left hand side is equal to right hand side or vice versa.
Starting from the left hand side
cos²x - sin²x ... 1
According to Pythagoras theorem, we know that x²+y² = r² in a right angled triangle. Coverting this to polar form, we have:
x = rcostheta
y = rsintheta
Substituting into the Pythagoras firnuka we have
(rcostheta)²+(rsintheta)² = r²
r²cos²theta+r²sin²theta = r²
r²(cos²theta+sin²theta) = r²
(cos²theta+sin²theta) = 1
sin²theta = 1 - cos²theta
sin²x = 1-cos²x ... 2
Substituting equation 2 into 1 we have;
= cos²x-(1-cos²x)
= cos²x-1+cos²x
= 2cos²x-1 (RHS)
This shows that cos²x -sin²x = 2cos²x-1 with the aid of PYTHAGORAS THEOREM
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Answer:
6x²y²
Step-by-step explanation:
6: 1 2 3 6
18: 1 2 3 6 9 18
36: 1 2 3 4 6 9 12 18 36
the common factor for 6 18 and 36 are
1 2 3 6
x² = x × x
y³ = y × y × y
x³ = x × x × x
y³ = y × y × y
x³ = x × x × x
y² = y × y
the common factor are for x and y are
x² y²
Multiply the GCF of the numerical part 6 and the GCF of the variable part x² y² to get 6x² y²
Answer:
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