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kiruha [24]
3 years ago
5

A piggy bank contains only quarters and dimes. A representative sample has 6 quarters and 2 dimes. If there are 56 coins in the

bank, how many coins are quarters? (SHOW WORK and LABEL your answer)
Mathematics
1 answer:
nadezda [96]3 years ago
8 0

Answer:

2

Step-by-step explanation:

Method- 56-25=31-25=6

I subtracted 25 until I cant no more so I only did it 2 times so 2 quarters are in the piggy bank.

Quarters-2

Then since the remainder was 6 that means there was only 1 penny and 1 nickel.

Pennies- 1

Nickels-1

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Tell whether each function is linear or non-linear.
MrMuchimi

Answer:

Function A is non-linear and Function B is linear.

Step-by-step explanation:

Linear function:

Has the following format:

y = mx + b

In which m is the slope and b is the y-intercept.

In a linear function, when x changes by 1, y will always changes by the same amount.

Function A:

When x changes by 1, y can change by various amounts. So function A is non-linear.

Function B:

y = -x + 5

In the format of a linear function, so linear

3 0
2 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
Write an equation in slope-intercept form: (1,6) and (2,3) are on the line
s344n2d4d5 [400]

Step-by-step explanation:

eqn of line : y = mx+ c

m = slope or gradient

c = y-intercept.

Lets take (1,6) = (x1,y1) and (2,3) = (x2,y2)

m \:  =  \frac{y1 - y2}{x1 - x2}  \\  =  \frac{6 - 3}{1 - 2}  \\ =  \frac{3}{ - 1}  \\  =  - 3

Substitute x = 1 and y = 6 into equation,

6 = ( - 3)(1) + c \\ 6 =  - 3 + c \\ c = 6 + 3 \\  = 9

Therefore substituting m and c value, equation of line is

y =  - 3x + 9

5 0
2 years ago
4) Solve Ax + By = C, for y
irina1246 [14]

Answer:Ax + By = C

-ax -ax

-------------------

By = -Ax + C

--- ------------

B B

--------------------

y = -Ax + C

----------

B

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Point D is 1/2 of the distance between which two points?
USPshnik [31]

Answer:

B and E

Step-by-step explanation:

B = - 6, D = - 2, E = 2

d(B, D) = - 2-(-6)= - 2 + 6 = 4 units

d(D, E) 2 - (-2) = 2 + 2 = 4

Since, d( B, D) = d( D, E)

Therefore, Point D is 1/2 of the distance between B and E.

5 0
3 years ago
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