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BartSMP [9]
3 years ago
10

A mosquito accelerates at a rate of 0.4 m/s2 for an unknown amount of time. How long did the mosquito atcelerate if its velocity

changed from
0.2 m/s to 1.5 m/s?
answer =
Do not include units in your answer. Round all answers to 2 decimal places if possible.

Mathematics
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

3.25 seconds.

Step-by-step explanation:

We can use the formula <em>Final Velocity = Initial Velocity + Acceleration * Time </em> to solve this problem.

First, we plug in the values we already know, and then we solve like normal:

1.5 = 0.2 + 0.4*t

1.3 = 0.4 * t

3.25 = t

Therefore, the mosquito accelerated for 3.25 seconds.

If this helped please consider giving me brainliest.

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Ken has a pole that is 26 inches long. He wishes to cut it into two pieces so that one piece will be 8 inches
bazaltina [42]

Answer:

im too immature for this lol...9. the answer is 9 inches

Step-by-step explanation:

9+9=18

18+8=26

4 0
1 year ago
Aaron wants to mulch his garden. His garden is x^2+18x+81 ft^2 One bag of mulch covers x^2-81 ft^2 . Divide the expressions and
blsea [12.9K]

Answer:

Step-by-step explanation:

Given

Garden: x^2+18x+81

One Bag: x^2 - 81

Requires

Determine the number of bags to cover the whole garden

This is calculated as thus;

Bags = \frac{x^2+18x+81}{x^2 - 81}

Expand the numerator

Bags = \frac{x^2+9x+9x+81}{x^2 - 81}

Bags = \frac{x(x+9)+9(x+9)}{x^2 - 81}

Bags = \frac{(x+9)(x+9)}{x^2 - 81}

Express 81 as 9²

Bags = \frac{(x+9)(x+9)}{x^2 - 9\²}

Evaluate as difference of two squares

Bags = \frac{(x+9)(x+9)}{(x - 9)(x+9)}

Bags = \frac{(x+9)}{(x - 9)}

Hence, the number of bags is Bags = \frac{(x+9)}{(x - 9)}

3 0
3 years ago
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8 0
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Which equation results from taking the square root of both sides (x-9)^2=81
mestny [16]
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3 0
3 years ago
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Ayso has 18 8th grade boys teams this year but this is a 28% decrease from the prior year. How many 8th grade teams were there l
NikAS [45]

Answer:

23pupils

Step-by-step explanation:

Given parameters:

Number of 18th grade boys this year = 18

Percentage decrease  = 28%

Unknown:

How many 8th grade teams were there last year  = ?

Solution:

Since this is a percentage decrease, ;

     Number of pupils this year  = Number of pupils last year - (28% x 18 )

                  18 + (28% x 18 ) = Number of pupils last year

         Number of pupils last year = 23pupils

4 0
3 years ago
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