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BartSMP [9]
3 years ago
10

A mosquito accelerates at a rate of 0.4 m/s2 for an unknown amount of time. How long did the mosquito atcelerate if its velocity

changed from
0.2 m/s to 1.5 m/s?
answer =
Do not include units in your answer. Round all answers to 2 decimal places if possible.

Mathematics
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

3.25 seconds.

Step-by-step explanation:

We can use the formula <em>Final Velocity = Initial Velocity + Acceleration * Time </em> to solve this problem.

First, we plug in the values we already know, and then we solve like normal:

1.5 = 0.2 + 0.4*t

1.3 = 0.4 * t

3.25 = t

Therefore, the mosquito accelerated for 3.25 seconds.

If this helped please consider giving me brainliest.

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Answer:

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Step-by-step explanation.

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Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

Part b

From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

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tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

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