Find the value of 45\75=5

Someone help me please with this algebra problem

aleksandr82 [10.1K]

Answer:

4

Step-by-step explanation:

3r = 10 + 5s

r = 10

3(10) = 10 + 5s

30 = 10 + 5r

20 = 5r

r = 4

7 0

3 years ago

Best Buy is displaying 15 laptops for a big store sale. The laptops include 6 identical Dells, 4 identical Chromebooks, and 5

Alchen [17]

Answer:

630,630 different arrangements are possible for the given laptops.

Step-by-step explanation:

Total number of laptops = n = 15

Number of identical Dell laptops = 6

Number of identical Chromebooks = 4

Number of identical Mackbooks = 5

We have to find in how many ways can the laptops be arranged. Number of arrangement of objects is calculated using Permutations as the order of objects matter during the arrangement. The formula to calculate the number of possible arrangements when there are similar objects is given as:

$\frac{n!}{a!b!c!...}$

Here n is the total number of objects and a,b, and c represent the number of identical objects. Using the given values we get:

$\frac{15!}{6!4!5!} = 630630$

This means 630,630 different arrangements are possible for the given laptops.

4 0

3 years ago

Just number 14 pls <br> Zoom in if needed

o-na [289]

A, dilation because the shape got larger. The other three options just move it around

8 0

3 years ago

A die is rolled. If you roll a 1, 2 or 3, you will toss 10 coins. If you roll a 4, 5 or 6, you will toss 20 coins. Let X denote

trasher [3.6K]

Answer:

a) The support of X is {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}

b) The mean of X is 7.5

c) The variance of X is 10

Step-by-step explanation:

a) Since you can toss up to 20 coins, and from that you can obtain any number of heads from 0 to 20, then the support of X {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20}.

b) To compute the mean of X, we need to see how is the <em>behavior</em> of X. Since 3 dices will gives 10 coins to toss and the other 3 will give us 20, then there is a probability of 1/2 that we tossed 10 coins and a probability of 1/2 that we tossed 20.

The random variable X, conditioned to the event 'The dice is 1,2 or 3' (or equivalently, 10 coins are tossed), will have a binomial distribution with paramenters n = 10, p = 1/2. The mean of X in this case is np = 5. If X is conditioned to the event 'The dice is 4,5 or 6', then X will have also binomial distribution, but this time with paramenters n = 20, p = 1/2. The mean of X in this case is 20*1/2 = 10.

Since each event we conditioned in had probability 1/2 to occur, then E(X) = 1/2 * 5 + 1/2 * 10 = 7.5.

c) Remember that V(X) = E(X²)- E(X)². Since we alredy know the mean of X, we just need to compute the mean of X squared.

The variance of a binomial distribution Z with paramenters n and p is

V(Z) = np(1-p)

since V(Z) = E(Z²)- E(Z)² = E(Z²)- n²p², then

E(Z²) = V(Z) + E(Z)² = np(1-p) + n²p² = p²(n²-n) + np

Therefore

E(X²) = E(X² | 10 coins are tossed) * 1/2 + E(X² | 20 coins are tossed) * 1/2 =

1/2*(0.5²(10²-10) + 5) + 1/2*(0.5²(20²-20) + 10) = 13.75 + 52.5 = 66.25

As a consecuence

V(X) = 66.25 - 7.5² = 10

The variance of X is 10.

5 0

3 years ago

Find the missing side length. If necessary, round to the nearest tenth.

Sphinxa [80]

Answer:

25

Step-by-step explanation:

Let's call the missing side (the hypotenuse) c.

c² = 7²+24² (according to the pythagorean theorem)

c= $\sqrt{625}$

c=25

7 0

3 years ago