Can someone help me with this??

Mathematics

1 answer:

timurjin [86]4 years ago

6 0

The volume for a triangular pyramid would be V=1/3AH, where A is the area or the triangular base, and H would be the height.
We need to find the area first. We can input the formula of the area of the triangular base, so it would be V=1/3(1/2bh)H.
In this problem, H=8, b=6, and h=4. Plug that in to the formula.
V=1/3(1/2*6*4)8. We can put that into a calculator, and get 32 cubic feet as our answer.

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Which expression represents the volume of the prism?

Tamiku [17]

Answer:

x³-2x² = x2(x – 2) cubic units

Step-by-step explanation:

The volume of a prism is found by multiplying the base area by the height. The base area is a parallelogram and so the area is x*(x-2) = x² -2x.

Multiply this area by the height x.

V = x(x² - 2x) = x³-2x²

This is the same as x2(x – 2) cubic units.

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4 years ago

Suppose an airplane traveling in a circle at 138 m/s can turn in a circle with as much as 69.6 m/s of centripetal acceleration.H

Oksanka [162]

Answer: A. 9567m

i hope i'm correct let me know if i'm wrong

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3 years ago

Integrate dx/3sinx+4cosx

german

$\displaystyle\int\frac{\mathrm dx}{3\sin x+4\cos x}$

A standard approach would be the tangent half-angle substitution:

$t=\tan\dfrac x2\implies\mathrm dt=\dfrac12\sec^2\dfrac x2\,\mathrm dx$

Then

$\sin x=2\sin\dfrac x2\cos\dfrac x2\implies\sin x=\dfrac{2t}{1+t^2}$

$\cos x=\cos^2\dfrac x2-\sin^2\dfrac x2\implies\cos x=\dfrac{1-t^2}{1+t^2}$

from which we get

$\mathrm dx=\dfrac2{1+t^2}\,\mathrm dt$

So the integral becomes

$\displaystyle\int\frac{\frac2{1+t^2}}{\frac{6t}{1+t^2}+\frac{4(1-t^2)}{1+t^2}}\,\mathrm dt=\int\frac{\mathrm dt}{3t+2(1-t^2)}=-\int\frac{\mathrm dt}{2t^2-3t-2}$