Answer:
e. 
Step-by-step explanation:
It is given that,
The density of intergalactic space material is 
kg per cubic meter.
And the volume of intergalactic space material is 
So the mass of that much intergalactic space material is,
, where 'm' is the mass, and 'v' is the volume.
Putting the values we get,
It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is 
So the volume of lead is,
So the volume of lead is 
.
Answer:
83422.5 grass seeds
Step-by-step explanation:
Applying,
A = 1/2bh....................... Equation 1
Where A = Area of the Triangle, b = base, h = height.
But, from the diagram,
tanФ = 20/b
b = 20/tanФ.................. Equation 2
Substitute equation 2 into equation 1
A = 1/2(20/tanФ)(h)................ Equation 3
Given: h = 20 m, Ф = 40°
Substitute these values into equation 3
A = 1/2(20×20)/tan40°
A = 200/tan40°
A = 238.35 m²
If the seed company recommends planting approximately 350 grass seeds per square meter,
Therefore,
Number of grass seed need = (350×238.35)
Number of grass seed needed = 83422.5 grass seeds
Answer:
I think that the answer would be 126 cm3 .
Answer:
0.125
Step-by-step explanation:
