3 years ago

Find the slope of the line through the pair of points. A(2, 3), P(2, 9)

1 answer:

8 0

$A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\-------------------\\\\A(2;\ 3)\to x_1=2\ and\ y_1=3\\B(2;9)\to x_2=2\ and\ y_2=9\\\\m=\dfrac{9-3}{2-2}=\dfrac{7}{0}-divided\ by\ 0\\\\Answer:\ The\ slope\ unde fined. It's\ a\ vertical\ line\ x=2.$

You might be interested in

if the length of the rectangle is twice the width and the perimeter of the rectangle is 30 centimeters what is the length of the

Dominik [7]

If the perimeter equals 30 and the length is twice the width, then the length is equal to 20 and the width is equal to 10.

7 0

3 years ago

Prove that C(50,3) + C(50,4) = C(51,4)

valkas [14]

By definition of the binomial coefficient,

$C(n,k) = \dfrac{n!}{k!(n-k)!}$

so we have

$C(50,3) + C(50,4) = \dfrac{50!}{3!47!} + \dfrac{50!}{4!46!} \\\\ = \dfrac{50!}{3!46!} \left(\dfrac1{47} + \dfrac14\right) \\\\ = \dfrac{50!}{3!46!} \times \dfrac{51}{188} \\\\ = \dfrac{51!}{3!46!} \times \dfrac1{4\times47} \\\\ = \dfrac{51!}{4!47!} \\\\ = \dfrac{51!}{4!(51-4)!} = C(51,4)$