I believe it's 12 because 5*16=80. So, then you would subtract 4 from 16 and gat 12.
By "which is an identity" they just mean "which trigonometric equation is true?"
What you have to do is take one of these and sort it out to an identity you know is true, or...
*FYI: You can always test identites like this:
Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
sinx = 3/5 cscx = 5/3
cosx = 4/5 secx = 5/4
tanx = 4/3 cotx = 3/4
Then just plug them in and see if it works. If it doesn't, it can't be an identity!
Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.
Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)
Next is b. Here we have (cscx + cotx)² = 1. Let's take the square root of each side...cscx + cotx = 1. Now you should be able to see why this can't work as a Pythagorean Identity. There's always that test we can do for verification...5/3 + 3/4 ≠ 1, nor is (5/3 + 3/4)².
By process of elimination, a must be true. You can test w/ our example ratios:
sin²xsec²x+1 = tan²xcsc²x
(3/5)²(5/4)²+1 = (4/5)²(5/3)²
(9/25)(25/16)+1 = (16/25)(25/9)
(225/400)+1 = (400/225)
(9/16)+1 = (16/9)
(81/144)+1 = (256/144)
(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
6.804 kilograms = 15 Ib. I hope I'm right. I looked it up on google
Answer:
Data: for the 10 days of practice, we have:
0.5 hours 1 time.
0.75 hours 2 times
1 hour 3 times
1.25 hours 2 times
1.5 hours 1 time
2 hours 1 time.
A) the largest amount number of times that she practiced by the same amount of time is 3 (for the 1-hour practice)
The smallest is 1 ( for the 0.5h, 1.5h, and 2h practices)
the difference is 3 - 1 = 2.
B) the time that she practiced more times is 1 hour, she practiced that amount of time in 3 different days out of the 10 days.
C) the equation can be found by multiplying the number of hours by the number of times that she practiced that amount of time, and then adding all of them:
0.5h*1 + 0.75h*2 + 1h*3 + 1.25h*2 + 1.5h*1 + 2h*1
D) the solution for the previous equation is 11 hours. Here the correct option is A.
Answer:
x
Step-by-step explanation:
(–3÷(–3/(x–2)))+2
=((–3×(x–2))÷(–3))+2
=(1×(x–2)÷1)+2
=(x–2)+2
=x
