11
(9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99)
Those numbers divisible by 9 are the multiple of 9; thus need to know how many multiples of 9 there are between 1 and 100:
100 ÷ 9 = 11 r 1 ÷ last multiple of 9 is 11 × 9 (= 99)
→ There are 11 - 1 + 1 = 11 numbers between 1 and 100 which are divisible by 9.
(They are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.)
Answer:
3.5 hour driving at 65 miles per hour
1/3(base area)(height)
base area= 22.1*14=154.7
1/3(154.7)(19)= 979.77
Answer: 1.11
Step-by-step explanation:
with tangent I guess A+B=C, B goes over A. But like I bet you're wondering how will yk which is a or b? idk either, but I tried my luck and got it right. So yk how C (hypotenuse) is always the biggest number? Well whichever number is bigger (A or B) the bigger number will go over the smaller one and then you round it to the nearest hundredth. I'm not good at rounding, so I used Math//way to get it for me. So it could be like , 12+36=40 (just picking random numbers), 36 will go over 12. And then you round it. I hope thus makes sense, it's 5:40AM rn. I should be sleep because I have a job interview at 3PM today.
Plug in 3 for h and 27 for g. Then multiply 2 and 27 which equal 54 then subtract by 3. remember 3 is smaller than 54 so it turns into a negative so its -51
