Answer:
Step-by-step explanation:
There isn't really a correct answer, because reading the data associated the line will have a margin of error. What I read it as and what you read it as would be slightly different. With that said I will try my best.
I need at least two points on the line that seem accurate.
I like one point at Latitude 40 and temperature 51 call it 50 (40, 50)
Another point I like is Latitude 15 and temperature 81 or 80 (15, 80)
to find the line we use the slope and one point on the line
with two points you can calcuate the slope m = Δy / Δx
m = (50 - 80) / (40 - 15)
= -30 / 25
= - 1.2
now find the y intercept y when x = 0 (the x -axis)
y - y1 = m ( x - x1 ) point 1 (40, 50) slope of -1.2
y - 50 = -1.2 ( 0 - 40)
y = -1.2(-40) + 50 i combined a few steps here to solve for y
y = 98
so from your data and line I get an answer of
y = -1.2x + 98
to double check my answer I used a graphing calculator to do all of the work!
the graphing calculator (attached image) using linear regression got an answer of
y = -0.983667x + 103.9
Answer:
Domain: 
Step-by-step explanation:
The domain of a function is all values of x such that f(x) exists.
In our case we have the following function:
We know that x and f(x) are real numbers, therefore the domain will be the interval , or in other words, the domain is all real numbers.
I hope it helps you!
Answer:
μ = 5.068 oz
Step-by-step explanation:
Normal distribution formula to use the table attached
Z = (x - μ)/σ
where μ is mean, σ is standard deviation, Z is on x-axis and x is a desired point.
98% of 6-oz. cups will not overflow means that the area below the curve is equal to 0.49; note that the curve is symmetrical respect zero, so, 98% of the cases relied between the interval (μ - some value) and (μ + some value)].
From table attached, area = 0.49 when Z = 2.33. From data, σ = 0.4 oz and x = 6 oz (maximum capacity of the cup). Isolating x from the formula gives
Z = (x - μ)/σ
2.33 = (6 - μ)/0.4
μ = 6 - 2.33*0.4
μ = 5.068
This means that with a mean of 5 oz and a standard deviation of 0.4 oz, the machine will discharge a maximum of 6 oz in the 98% of the cases.
X<67/5 :) do u need the work or nah
