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pshichka [43]
4 years ago
11

I need help I do not get it please help

Mathematics
2 answers:
Arisa [49]4 years ago
7 0

4/6 = 2 x 2 = 4
= 3 x 2 = 6
Ans : 2/3

10/15 = 2 x 5 = 10
3 x 5 = 15
Ans : 2/3




zhenek [66]4 years ago
4 0
The first fraction is 4 over 6, right? hopefully it is, i cant really see. 
Basically, you can divide 4 and 6 by the same number, they have factors in common. They're both multiples of 2. if you divide them both by 2, you get 2 over 3, which is the <em>exact same amount as 4 over 6, it's just written in a simpler way. </em>the first answer is 2 over 3.

What numbers can both 10 and 15 be divided by? give it a try.
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Step-by-step explanation:

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3 years ago
SOMEONE HELP :'(((
jeka57 [31]

Answer:

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3 years ago
If w = 6 units, x = 3 units, and y = 5 units, what is the surface area of the figure?
Dima020 [189]

*see attachment for the diagram

Answer:

A. 178 units²

Step-by-step explanation:

Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)

✔️Surface area of the square pyramid = s² + 2*s*l

Where,

s = side length of square base (w) = 6 units

l = slant height = ?

Use Pythagorean theorem to find l

l = √((w/2)² + y²)

l = √((6/2)² + 5²) = √(9 + 25)

l = √34

l ≈ 5.8 units

Surface area of the square pyramid = 6² + 2*6*5.8 = 105.6 units²

✔️Surface area of square prism:

SA = 2a² + 4ah

Where,

a = w = 6 units

h = x = 3 units

Substitute

SA = 2(6²) + 4*6*3

= 72 + 72

= 144 units²

✔️base area of the square pyramid = s²

s = w

Base area = 6²

Base area = 36 units²

✅Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)

Surface area of the figure = (105.6 + 144) - 2(36)

= 249.6 - 72

= 177.6

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7 0
3 years ago
Evaluate 5j +12 foreach listed<br> value ofn.<br> j= 4<br> j = 6
Bezzdna [24]

Answer: 32 and 42

Step-by-step explanation:

5j +12

j= 4

j = 6

5(4) + 12

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5(6) + 12

5 times 6 = 30

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6 0
3 years ago
Read 2 more answers
If enrollment increases by approximately the same
Tanya [424]

Given:

The enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased between 1950 and 1960.

To find:

The expected enrollment in 2010.

Solution:

Percentage decrease formula:

\%\text{ decrease}=\dfrac{\text{Initial value - New value}}{\text{Initial value}}\times 100

The percentage decrease in between 1950 and 1960 is:

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\%\text{ decrease}=\dfrac{0.5}{4}\times 100

\%\text{ decrease}=\dfrac{50}{4}

\%\text{ decrease}=12.5

The enrollment decreased by 12.5% between 1950 and 1960. So, the enrollment increases by 12.5% between 2000 and 2010.

The expected enrollment in 2010 is:

\text{Expected enrollment}=7+\dfrac{12.5}{100}\times 7

\text{Expected enrollment}=7+0.875

\text{Expected enrollment}=7.875

Therefore, the expected enrollment in 2010 is 7.875 thousands.

4 0
3 years ago
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