1. You can solve this problem and calculate the volume of the cooler, by following the proccedure below:
2. You have that the cooler measures <span>1 1/2 feet by 1 foot by 1 1/5 feet; then, you only have to multiply these values. Then, you have:
1 1/2 feet=1.5 feet
1 1/5 feet=1.2 feet
Volume of the cooler=(1.5 feet)(1 foot)(1.2 feet)
Volume of the cooler=1.8 feet</span>³
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What is the volume of the cooler?
The answer is: T</span>he volume of the cooler is 1.8 feet<span>³</span><span>
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Answer:
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Step-by-step explanation:
Let
S = 2b/(b+a)^2 + 2a/(b^2-a^2) factor denominator
= 2b/(b+a)^2 + 2a/((b+a)(b-a)) factor denominators
= 1/(b+a) ( 2b/(b+a) + 2a/(b-a)) find common denominator
= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a)) expand
= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a)) simplify & factor
= 2/(b+a)(b^2+a^2)/((b+a)(b-a)) simplify & rearrange
= 2(b^2+a^2)/((b+a)^2(b-a))
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Answer:
The Quadratic Formula: Given a quadratic equation in the following form:
ax2 + bx + c = 0
...where a, b, and c are the numerical coefficients of the terms of the quadratic, the value of the variable x is given by the following equation:
\small{ x = \dfrac{-b \pm \sqrt{b^2 - 4ac\phantom{\big|}}}{2a} }x=
2a
−b±
b
2
−4ac
∣
∣
∣
Step-by-step explanation:
<span>1284720 is the answer to the first one
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<span>267120 is the answer to the second one</span>
