Answer:
Move L, Q, and K down 2 spaces, and right 4 spaces.
Step-by-step explanation:
Answer:
The natural no between 2 to 15 is 2,3,4,5,6,7,8,9,10,11 and 12. prime numbers among these are 2,3,5,7 and 11. therefore,out of 11 number, 5 are prime number.what fraction of the natural numbers between 2 and 15 are prime numbersthe length of abhishek's notebook is 17cm and 8 mm. What will be its length in cm
*see attachment for the diagram
Answer:
A. 178 units²
Step-by-step explanation:
Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)
✔️Surface area of the square pyramid = s² + 2*s*l
Where,
s = side length of square base (w) = 6 units
l = slant height = ?
Use Pythagorean theorem to find l
l = √((w/2)² + y²)
l = √((6/2)² + 5²) = √(9 + 25)
l = √34
l ≈ 5.8 units
Surface area of the square pyramid = 6² + 2*6*5.8 = 105.6 units²
✔️Surface area of square prism:
SA = 2a² + 4ah
Where,
a = w = 6 units
h = x = 3 units
Substitute
SA = 2(6²) + 4*6*3
= 72 + 72
= 144 units²
✔️base area of the square pyramid = s²
s = w
Base area = 6²
Base area = 36 units²
✅Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)
Surface area of the figure = (105.6 + 144) - 2(36)
= 249.6 - 72
= 177.6
≈ 178 units²
Answer: 32 and 42
Step-by-step explanation:
5j +12
j= 4
j = 6
5(4) + 12
5 times 4 = 20
20 + 12 = 32
5(6) + 12
5 times 6 = 30
30 + 12 = 42
Given:
The enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased between 1950 and 1960.
To find:
The expected enrollment in 2010.
Solution:
Percentage decrease formula:

The percentage decrease in between 1950 and 1960 is:




The enrollment decreased by 12.5% between 1950 and 1960. So, the enrollment increases by 12.5% between 2000 and 2010.
The expected enrollment in 2010 is:



Therefore, the expected enrollment in 2010 is 7.875 thousands.