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Svetlanka [38]
2 years ago
12

Given h(x)=-x-4, find h (-6)

Mathematics
2 answers:
Mumz [18]2 years ago
5 0
2

explanation:

h(x)= -x-4

h(-6) = -(-6)-4
h(-6) = 6-4
h(-6) = 2

Mademuasel [1]2 years ago
4 0

Answer:6

Step-by-step explanation:

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Simplify (x + 2/ x^2 + 2x -3) / (x + 2/x^2 - x)
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Answer:

The simplest form is x/(x + 3)

Step-by-step explanation:

* To simplify the rational Expression lets revise the factorization

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*  To factor a quadratic in the form x² ± bx ± c:

- First look at the c term  

# If the c term is a positive number, and its factors are r and s they

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#  If the c term is a negative number, then either r or s will be negative

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- Second look at the b term.  

# If the c term is positive and the b term is positive, then both r and

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Ex: x² + 5x + 6 = (x + 3)(x + 2)  

# If the c term is positive and the b term is negative, then both r and s

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# If the c term is negative and the b term is positive, then the factor

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# If the c term is negative and the b term is negative, then the factor

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* Now lets solve the problem

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∵ The numerator is \frac{x+2}{x^{2}+2x-3}

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- The last term is negative then the two brackets have different signs

∵ 3 = 3 × 1

∵ 3 - 1 = 2

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∵ The denominator is \frac{x+2}{x^{2}-x}

- Factorize its denominator

∵  The denominator = x² - 2x

- Take x as a common factor and divide each term by x

∵ x² ÷ x = x

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∴ The fraction = \frac{x+2}{(x+3)(x-1)} ÷ \frac{x+2}{x(x-1)}

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∴ The simplest form = \frac{x}{x+3}

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