What is the volume of the composite figure?
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Create a frequency chart by using a bar graph as shown in the picture below. A frequency chart is used when you want to present how much of the data belongs to one group. For this problem, it specifically represents how many people belong to a time interval. The y-axis is the number of people and the x-axis is the time expressed in intervals.
As you can see visually, the shape of the distribution graph is skewed to the right, although not uniformly. This is justified because the relatively high data are situated on the far right side of the graph. Also, there are no outliers in the data because they are all pretty close to each other. No bar is obviously different from the others. The center is the median of all the data. If you create a middle line as represented by the horizontal line, the center data point is 21. You can verify this by arranging all the data points from smallest to largest, and selecting the middle data. Lastly, the spread is from the lowest value to the highest value. The lowest value is at 12 to 1 pm with 19 people. The highest value is at 4 to 5 pm with 24 people. Therefore, the spread is from 19 to 24.
As you can see visually, the shape of the distribution graph is skewed to the right, although not uniformly. This is justified because the relatively high data are situated on the far right side of the graph. Also, there are no outliers in the data because they are all pretty close to each other. No bar is obviously different from the others. The center is the median of all the data. If you create a middle line as represented by the horizontal line, the center data point is 21. You can verify this by arranging all the data points from smallest to largest, and selecting the middle data. Lastly, the spread is from the lowest value to the highest value. The lowest value is at 12 to 1 pm with 19 people. The highest value is at 4 to 5 pm with 24 people. Therefore, the spread is from 19 to 24.
We have that
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.
<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.