Question

Pls find the zeros in 10th level​

Answer 1

Answer:

x = - 3$\sqrt{2}$, x = $\sqrt{2}$

Step-by-step explanation:

Given

x² + 2$\sqrt{2}$ x - 6

To calculate the zeros equate to zero

x² + 2$\sqrt{2}$ x - 6 = 0 ( add 6 to both sides )

x² + 2$\sqrt{2}$ x = 6

One way is to use the completing the square method

add ( half the coefficient of the x- term )² to both sides

x² + 2$\sqrt{2}$ x + ($\sqrt{2}$)² = 6 + ($\sqrt{2}$)²

x² + 2$\sqrt{2}$ x + 2 = 6 + 2

(x + $\sqrt{2}$ )² = 8

Take the square root of both sides

x + $\sqrt{2}$ = ± $\sqrt{8}$ = ± 2$\sqrt{2}$

subtract $\sqrt{2}$ from both sides

x = - $\sqrt{2}$ ± 2$\sqrt{2}$

x = - $\sqrt{2}$ - 2$\sqrt{2}$ = - 3$\sqrt{2}$, or

x = - $\sqrt{2}$ + 2$\sqrt{2}$ = $\sqrt{2}$