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3 years ago

Use the figure to answer the questions.

Mathematics

1 answer:

Advocard [28]3 years ago

4 0

Answer:

a) Triangle ABE is similar to Triangle DCE by Angle-Angle-Angle postulate.

b) 4 cm

Step-by-step explanation:

a) angle A = angle D

And

angle B = angle C

(Alternate angles)

Angle AEB = Angle DEC

(Vertically opposite angles)

All three angles are equal, hence triangles are similar

AB/DC = AE/DE

6/15 = y/10

y = 6×10/15

y = 4

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Lisa is performing a study regarding the average height of roses grown using an organic fertilizer. Her population

GuDViN [60]

Answer:

Every fifth rose in each row of roses

Step-by-step explanation:

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3 years ago

Read 2 more answers

Write a formula for quadratic function if its graph has the vertex at point (0,6) and passes through the point (−1,−2).

d1i1m1o1n [39]

Answer:

y = - 8x² + 6

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (0, 6), thus

y = a(x - 0)² + 6, that is

y = ax² + 6

To find a substitute (- 1, - 2) into the equation

- 2 = a(- 1)² + 6, that is

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- 8 = a

y = - 8x² + 6

4 0

3 years ago

What is 485=? Tens +5units

spin [16.1K]

48 ten units and 1 five unit.

4 0

3 years ago

Michael’s weight can be represented by the expression 72x^5. Al’s weight can be represented by the expression 9x^7.

podryga [215]

Answer:

a) $\frac{72x^5}{9x^7}$

b) $=\frac{8}{x^2}$

c), Yes; $8x^2$

Step-by-step explanation:

Michael's Weight: $72x^5$

Al's weight: $9x^7$

a) Ratio of Michael's weight to Al's weight: $\frac{72x^5}{9x^7}$

b) This ratio simplifies to: $\frac{8\times 9x^5}{9x^5\timesx^2}$

$=\frac{8}{x^2}$

c) Yes, If the exponent in each expression were negative, then we have:

Ratio of Michael's weight to Al's weight: $\frac{72x^{-5}}{9x^{-7}}$

This ratio simplifies to: $8x^{-5--7}=8x^2$

The two ratios are not the same.

3 0

3 years ago

I need help on 10 please explain

kumpel [21]

Lets approach this problem differently
15 gallons ....you drive ......330 miles lets divide both numbers by 15 to find out how much you can go with 1 gallon
1 gallon..... you drive.....330/15=22
you car goes 22 miles per 1 gallon
if you put 20 gallons
20*22=440 miles

6 0

3 years ago