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tigry1 [53]
2 years ago
15

Please help me right away.

Mathematics
1 answer:
velikii [3]2 years ago
4 0
I’m pretty sure it’s c , sorry if it’s wrong tho
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12. Find x. (x + 20)° (5x - 8)°​
ololo11 [35]

Answer:

<h2>x = 7</h2>

Step-by-step explanation:

Simplifying

x + 20 = 5x + -8

Reorder the terms:

20 + x = 5x + -8

Reorder the terms:

20 + x = -8 + 5x

Solving

20 + x = -8 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

20 + x + -5x = -8 + 5x + -5x

Combine like terms: x + -5x = -4x

20 + -4x = -8 + 5x + -5x

Combine like terms: 5x + -5x = 0

20 + -4x = -8 + 0

20 + -4x = -8

Add '-20' to each side of the equation.

20 + -20 + -4x = -8 + -20

Combine like terms: 20 + -20 = 0

0 + -4x = -8 + -20

-4x = -8 + -20

Combine like terms: -8 + -20 = -28

-4x = -28

Divide each side by '-4'.

x = 7

Simplifying

x = 7

8 0
3 years ago
Choose the equation in point slope form that passes through the point (3,-4) and has a slope of 4
netineya [11]

Answer:

y+4=4(x-3)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-4)=4(x-3)

y+4=4(x-3)

4 0
3 years ago
The price of an item is $35 but you have to pay $38.22 what is the sale tax rate?
Vilka [71]
3.22$ because your originally spending 35$ so the added 3.22$ makes up 38.22$
6 0
3 years ago
Solve for x in the equation x2 + 4x-4=8.
iren [92.7K]

{x}^{2}  + 4x - 4 = 8 \\  =  >  {x}^{2}  + 4x - 4 - 8 = 0 \\  =  >  {x}^{2}  + 4x - 12 = 0 \\  =  >  {x}^{2}  + 6x  - 2x - 12 = 0 \\  =  >  x(x + 6) - 2(x + 6) = 0 \\  =  > (x - 2)(x + 6) = 0 \\  =  > x = 2 \:  \:  \: or \:  \:  \: x =  - 6

<u>Answer</u><u>:</u>

x = -6 or x = 2

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0
2 years ago
Evaluate the cosine if the angle of rotation which contains the point (9, -3) on its terminal side
Liono4ka [1.6K]

so we know the terminal point is at (9, -3), now, let's notice that's the IV Quadrant

\bf (\stackrel{x}{9}~~,~~\stackrel{y}{-3})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{9^2+(-3)^2}\implies c=\sqrt{81+9}\implies c=\sqrt{90} \\\\[-0.35em] ~\dotfill

\bf cos(\theta )=\cfrac{\stackrel{adjacent}{9}}{\stackrel{hypotenuse}{\sqrt{90}}}\implies \stackrel{\textit{rationalizing the denominator}}{\cfrac{9}{\sqrt{90}}\cdot \cfrac{\sqrt{90}}{\sqrt{90}}\implies \cfrac{9\sqrt{90}}{90}}\implies \cfrac{\sqrt{90}}{10}\implies \cfrac{3\sqrt{10}}{10}

6 0
3 years ago
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