Help please fast! no explanation!!!

Consider the following relation:(1,12) (3.8) (3,11) (6,9) (7,11) . Which ordered pair could be removed so that the relation is a

Y_Kistochka [10]

You could remove 3,11)

6 0

3 years ago

Select True or False for each statement.

SSSSS [86.1K]

$\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32$

TRUE

$\sqrt[5]{36^4}=36^{4/5}$

which surely isn't 36. FALSE

$\sqrt{12} - \dfrac 2 5 \sqrt{75} = 2 \sqrt{3} -\dfrac 2 5 (5) \sqrt{3} = 0$

FALSE

For the fourth one we have a

$\sqrt{98b} + \sqrt{2b}$

which isnt

$10\sqrt{b}$

so this is FALSE.

$\dfrac{1}{(\sqrt 5 - \sqrt 6)^2}$

$= \dfrac{1}{(\sqrt 5 - \sqrt 6)^2} \cdot \dfrac{(\sqrt 5 + \sqrt 6)^2}{(\sqrt 5 + \sqrt 6)^2}$

$= \dfrac{(\sqrt 5 + \sqrt 6)^2}{ ( (\sqrt 5 - \sqrt 6)(\sqrt 5 + \sqrt 6))^2}$

$= \dfrac{(\sqrt 5 + \sqrt 6)^2}{( 5-6)^2}$

$=(\sqrt 5 + \sqrt 6)^2$

No fractions in that one so FALSE.

3 0

3 years ago

A farmer plowed a rectangular section of land for a new crop. The section measures 24 1/2 yd by 38 1/2 yd. Find the total area i

MAVERICK [17]

Answer: $943\dfrac{1}{4}\text{ sq. yds}$

Step-by-step explanation:

Given , A farmer plowed a rectangular section of land for a new crop.

Dimensions of the section is given by :-

Length by width = $24\dfrac{1}{2}\text{ yd by }38\dfrac{1}{2}\text{ yd}$

Since , the area of a rectangle = length x width

Then, the total area in yards of plowed section of land will be:

$24\dfrac{1}{2}\times38\dfrac{1}{2}\text{ sq. yds}\\\\=\dfrac{2(24)+1}{2}\times\dfrac{2(38)+1}{2}\text{ sq. yds}\\\\=\dfrac{49}{2}\times\dfrac{77}{2}\text{ sq. yds}\\\\=\dfrac{3773}{4}\text{ sq. yds}\\\\=943\dfrac{1}{4}\text{ sq. yds}$

Hence, the total area in yards of plowed section of land = $943\dfrac{1}{4}\text{ sq. yds}$

8 0

3 years ago

The information above describes the real GDP per capita for a country for the period from 1985 through to 2001. If a new busines

topjm [15]

Answer:

The question is incomplete, here is the complete question.

Year Real GDP per Capita

1985 6,000

1986 6,300

1987 6,700

1988 7,200

1989 7,850

1990 8,250

1991 8,450

1992 8,550

1993 8,575

1994 8,510

1995 8,370

1996 8,100

1997 7,950

1998 7,925

1999 7,960

2000 8,035

2001 8,155

The information above describes the real GDP per capita for a country for the period from 1985 through to 2001. If a new business cycle began in 1985, how long was this cycle? In which year did the peak occur? The trough occurred in which year? How long was the expansion? How long was the recession?

Step-by-step explanation:

a.If a new business cycle began in 1985, how long was this cycle?

The business cycle describes the rise and fall in production output of goods and services in an economy. In the data given above, a business cycle is complete in the year 1998. If the cycle started in 1985 then it was 14 years long.

b. In which year did the peak occur? The trough occurred in which year?

In the data given above, the peak occured in year 1993 (GDP per capita of 8,575) and trough occurred in the year 1998 (GDP per capita of 7,925).

c. How long was the expansion? How long was the recession?

Expansion was 9 years long (1985-1993) and recession was of 5 years (1994-1998).

7 0

3 years ago

Hi! I need help on my homework. Juli uses 12 ounces of cheese in her potato soup recipe. Her recipe yields 8 servings. If Juli n

Anestetic [448]

12x8=96 then 96 divided by 20=4.8, so the answer is 4.8, your welcome! Hopefully you get it right!!☺️

3 0

3 years ago