Given,
Cylinder A has a volume of 6 cubic units
and height =3 units
The radius of cylinder A,
![\begin{gathered} r=\sqrt[]{\frac{V}{\pi h}} \\ =\sqrt[]{\frac{6}{3\pi}} \\ =0.8 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20r%3D%5Csqrt%5B%5D%7B%5Cfrac%7BV%7D%7B%5Cpi%20h%7D%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B%5Cfrac%7B6%7D%7B3%5Cpi%7D%7D%20%5C%5C%20%3D0.8%20%5Cend%7Bgathered%7D)
To find the volume of a cylinder B

Thus the volume of cylinder B is 6.03
Answer:
m<1=61
m<2=40
m<3=60
m<4=80
m<5=100
Step-by-step explanation:
180/3=60
180/9=20
20x2=40
20x4=80
20x3=60
59+60=119
180-119=61
180-80=100
A straight line (180o) is still an angle. Would you be wondering if the question said "Can 179o be a real angle?" No you would simply draw it. 1 degree more and you have 180o and it is an angle as well.
So you have a line that is both a line and an angle with A in the middle.
X is -10. I think, I might be wrong.
Question 1= would equal 63 but why is there no 63?(did you type the answers right? or the angles right?
47+70=117
180-117=63
question 2 would be 36
54+90=144
180-144=36