If the points P(5,2),Q(0,7) and R(-5,2) are drawn on coordinate plane,where must point S be located so that figure PQRS is squar
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Answer:
y = - x²
Step-by-step explanation:
Since the vertex is at the origin and the focus at (0, - 4) then the parabola opens vertically down with equation
x² = 4py ( p is the distance from the vertex to the focus )
Here p = - 4 ( focus is below the vertex ), thus
x² = 4(- 4)y = - 16y ( divide both sides by - 16 )
y = - x²