We must look at this question in steps
The first half of the journey is travelled at 40 km/h
Half of 100km is 50 km
Using the formula
Distance = Speed x Time
Speed = Distance / Time
Time = Distance / Speed
We can work out the time:

50km / 40km/h = 1.25 hours

Next we look at the second half of the journey
50km at 80km/h
50km / 80km/h = 0.625 hours

Add together both times to work out how long the entire journey took
1.25 + 0.625 = 1.875 hours

Using the Speed formula from before
Speed = 100km / 1.875 =
53 1/3 km/h or 53.3 recurring km/h

6 0

3 years ago

Simplify the equation

Arturiano [62]

Answer:

$\dfrac{16x^3-37x^2-16x+37}{x^2+2}$

Step-by-step explanation:

There aren't any factors that cancel (except 3x). The best you can do is multiply it out.

$\displaystyle\frac{\frac{3x^2-3}{x}}{\frac{3(x^2+2)}{16x^2-37x}}=\frac{3(x^2-1)}{x}\cdot\frac{16x^2-37x}{3(x^2+2)}\\\\=\frac{x(x^2-1)(16x-37)}{x(x^2+2)}=\frac{16x^3-37x^2-16x+37}{x^2+2}$

7 0

3 years ago

What is actively one pls pls pls i beg you

OLga [1]

Answer:

1. 9 to the power of 7

2. 7 to the power of 8

3. 10 to the power of 8.

4. 3 to the power of 9.

5. 2 to the power of 12.

Step-by-step explanation:

8 0

3 years ago

A ball is thrown upward from 3 feet iff the ground at an initial velocity of 64 feet per second. What is the maximum height the

Elza [17]

I found h max = 64 feet

Explanation: Ok...probably you can do this differently but I would try to find the vertex of the parabola describing the trajectory: 1) derive it: h ` ( t ) = 64 − 32 t 2) set derivative equal to zero: 64 − 32 t = 0 t = 64 32 = 2 sec 3) use this value of t into your trajectory: h ( 2 ) = h max 64 ⋅ 2 − 16 ⋅ 4 = 64 feet .

7 0

3 years ago