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Alex Ar [27]
2 years ago
10

If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

te A^c or B^c refers to A complement or B complement**
Mathematics
1 answer:
Effectus [21]2 years ago
4 0

If A and B are independent, then P(A\cap B)=P(A)P(B).

a.

P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)

P(A\cup B)=0.5+0.2-0.5\cdot0.2

\boxed{P(A\cup B)=0.6}

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)

P(A^c\cap B^c)=1-0.6

\boxed{P(A^c\cap B^c)=0.4}

c. DeMorgan's law can be used here too:

P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)

P(A^c\cup B^c)=1-0.5\cdot0.2

\boxed{P(A^c\cup B^c)=0.9}

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A bus driver pays all tolls, using only nickels and dimes, by throwing one coin at a time into the mechanical toll collector.
lutik1710 [3]

Answer: a) An = An-1 + An-2

b) 55ways

Step-by-step explanation:

a) a nickel is 5 cents and a dime is 10cent so a multiple of 5 cents is the possible way to pay the tolls in both choices.

Let An represents the number of possible ways the driver can pay a toll of 5n cents, so that

An = 5n cents

Case 1: Using a nickel for payment which is 5 cents, the number of ways given as;

An-1 = 5( n-1)

Case 2: using a dime which is two 5 cents, the number of ways is given as;

An-2 = 5(n-2)

Summing up the number of ways, we have

An = An-1 + An-2

From the relation,

If n= 0, Ao= 1

n =1, A1= 1

b) 45 cents paid in multiples of 5cents will give us 9 ways(A9)

From the relation, we have that

Ao = 1

A1 = 1

An =An-1 + An-2

Ao = 1

A1 = 1

A2 = A1+Ao = 1+1= 2

A3 = A2 + A1 = 3

A4 = A3+A2=5

A5=A4+A3=8

A6=A5+A4=13

A7 =A6+A5 = 21

A8= A7+A6= 34

A9= A8+A7= 55

So there are 55ways to pay 45cents.

4 0
2 years ago
Please help solve this
White raven [17]

Answer:

BC~=AD (GIVEN )

CBA=CDA (altanate angles BC=AD)

C=A (altanate angles (BC=AD)

AAS

brainyliest please

8 0
3 years ago
What value of x will make the given triangles congruent?
Molodets [167]
Because you're trying to make them congruent, equal the two expressions to each other. 

So, for #10 you would equal them so it would look like this. 
2x+2=5x-19

Then you would just go ahead and simplify

2x+2=5x-19
-2x     -2x
---------------
2= 3x -19
+19    +19
---------------
21=3x
---  ----
3     3

x=7

This means that x should be 7. You can check this just by plugging it in

2x+2
2(7)+2 = 16

5x-19
5(7)-19= 16

Same with #11.

x+8=3x-14
-x     -x
--------------
8=2x-14
+14   +14
--------------
22=2x
---  ----
2     2

x=11

Check. 

x+8
11+8= 19

3x-14
3(11) - 14 = 19
6 0
3 years ago
Hospital administrator Jake Rosen was recently convicted for fraud he committed against his employer, Cedar Hospital Systems. Ov
dexar [7]

Step-by-step explanation:

Employee frauds are one of most common form of frauds which can be detected in a company. There can be many types or forms of employee frauds.  

the major types are:

• Asset Misappropriation

• Bribery and Corruption

• Data theft

• Vendor Fraud

• Payroll Fraud

• Accounting Fraud

2. The hospital could have detected the fraud going on earlier if they had consulted the help of an audit firm this could have helped exposed the fraud earlier.

6 0
3 years ago
X2 + y2 - 14x + 10y + 65 = 0 <br><br> will lie ENTIRELY in Quadrant
Afina-wow [57]
Rearranging to standard form 
= (x - 7)^2 + (y + 5)^2 = -65 + 49 + 25
 (x-7)^2 + (y+5)^2 = 9 
so the centre is at (7,-5) and the radius is 3

so the circle will be entirely in Quadrant 4.
5 0
2 years ago
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