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frez [133]
3 years ago
12

Please help me with these questions and please show the work or something... and yep, 30 points so you better answer with an exp

lanation:
-Picking a red checker from a bag of 9 black checkers and 6 red checkers, replacing it, and picking another red checker. I said 4/25.

-Picking a black checker from a bag of 9 black checkers and 6 red checkers, replacing it, and picking another red checker. I said 6/25.

-Picking a black checker from a bag of 9 black checkers and 6 red checkers, replacing it, and picking another black checker.

-Rolling a 6 on the first roll of a 1-6 number cube and rolling a 3 on the second roll of the same cube.

-Rolling a 6 on the first roll of 1-6 number cube and rolling a 7 on the second roll of the same cube.

-Rolling a 1, 2, or 3 on the first roll of a 1-6 number cube and rolling a 4, 5, or 6 on the second roll of the same cube.
Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
Part 1:

You have the correct answer. You multiply the probability of getting red (6/15) by the probailitiy of getting red (6/15) to get 36/225 which reduces to 4/25

--------------------------------

Part 2: 

This is also correct. Nice work. You multiply the probability of getting black (9/15) with the probability of getting red (6/15) to get 54/225 = 6/25

--------------------------------

Part 3:

The probability of picking a black checker is 9/15. If a replacement is made, then the probability of picking another black checker is also 9/15. So, 

(9/15)*(9/15) = 81/225 = 9/25

Answer: 9/25

--------------------------------

Part 4:

The probability of rolling a 6 is 1/6. The probability of rolling a 3 is 1/6 as well. This is because there is only one side with this label out of 6 total. Multiply the probabilities

(1/6)*(1/6) = 1/36

Answer: 1/36

--------------------------------

Part 5:

It is impossible to roll a 7 on the six sided cube because the highest number is 6. Therefore the overall probability is 0

Answer: 0

--------------------------------

Part 6:

There are 3 outcomes we want (rolling a 1,2, or 3) out of 6 total. So the probability of rolling a 1,2 or 3 is 3/6 = 1/2. Similarly, the probability of rolling a 4, 5 or 6 is 3/6 = 1/2 as well.

Multiplying the probabilities gives

(1/2)*(1/2) = 1/4

Answer: 1/4
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Let AB = 24, AC = 10 and BC = 26.
nata0808 [166]

Answer:

a) 24

b) 10

c) 12/13

d) 5/13

e) 12/5

Step-by-step explanation:

a) We can see that the leg opposite <C is AB, and we are given AB = 24

b) We can see the leg adjacent to <C is AC, and we are given that AC = 10

c) The trig function sine is equal to

\frac{opposite}{hypotenuse}

The opposite, AB, is 24, and the hypotenuse, BC, is 26. We can plug those numbers in:

sin(c) = \frac{24}{26} = \frac{12}{13}

d)The trig function cosine is equal to

\frac{adjacent}{hypotenuse}

The adjacent, AC, is 10, and the hypotenuse, BC, is 26. We can plug those numbers in:

cos(c) = \frac{10}{26} = \frac{5}{13}

d)The trig function tangent is equal to

\frac{opposite}{adjacent}

The opposite, AB, is 24, and the adjacent, AC, is 10. We can plug those numbers in:

tan(c) = \frac{24}{10} = \frac{12}{5}

4 0
2 years ago
ABC bank requires a 20% down payment on all of its home loans if a house is priced at 185000 what is the amount of the down paym
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