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andrew-mc [135]
3 years ago
5

Evaluate.   4⋅( 1 4 −3 )+12

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0
4(14-3)+12
4x11+12
44+12
=56
Artemon [7]3 years ago
3 0
4.(14-3) + 12
4.11 + 12
44 + 12
56
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Is circle Tangent lines
Sergio [31]

no because it is not a right angled triangle.

this means angle A is not 90° so AB cant be a tangent.

4 0
3 years ago
The price of a bungalow in 1990 was $850000. If there was a 125% increase in 2000, followed by a 30% decrease in 2013, what was
astra-53 [7]

Answer:

1,338,750$

Step-by-step explanation:

1990 price was 850,000

in 2000

850,000 + 125% = 1,062,500

850,000 + 1,062,500 = 1,912,500

in 2013

1,912,500 - 30% = 573,750

1,912,500 - 573,750 = 1,338,750

6 0
2 years ago
For what value of c will this function have one zero?<br> f(x) = X^2 +c
Phoenix [80]
X² + c is actually a quadratic function.

And x² + c = 0,  it usually has two zeros which are solutions.

But for when c = 0,

x² + c = 0

x² + 0 = 0

x² = 0

Taking the square root of both sides.

x = 0.  Here it only has one zero.

So the function x² + c,  only has one root for  c = 0.
6 0
3 years ago
Solve the absolute value inequality |x+9| &gt; 3
Studentka2010 [4]

Answer:

x>−6,x<−12

Step-by-step explanation:

Break down the problem into these 2 equations.

x+9>3x+9>3

-(x+9)>3−(x+9)>3

Solve the 1st equation: x+9>3x+9>3.

x>-6x>−6

3 Solve the 2nd equation: -(x+9)>3−(x+9)>3.

x<-12x<−12

Collect all solutions.

x>-6,x<-12x>−6,x<−12

8 0
3 years ago
Find the standard deviation of the following data. Round your answer to one decimal place. x 0 1 2 3 4 5 P(X
lbvjy [14]

Answer:

<em></em>\sigma = 1.8<em></em>

<em></em>

Step-by-step explanation:

Given

\begin{array}{ccccccc}x & {0} & {1} & {2} & {3} & {4}& {5} \ \\ P(x) & {0.2} & {0.1} & {0.1} & {0.2} & {0.2}& {0.2} \ \end{array}

Required

The standard deviation

First, calculate the expected value E(x)

E(x) = \sum x * P(x)

So, we have:

E(x) = 0 * 0.2 + 1 * 0.1 + 2 * 0.1 + 3 * 0.2 + 4 * 0.2 + 5  * 0.2

E(x) = 2.7

Next, calculate E(x^2)

E(x^2) = \sum x^2 * P(x)

So, we have:

E(x^2) = 0^2 * 0.2 + 1^2 * 0.1 + 2^2 * 0.1 + 3^2 * 0.2 + 4^2 * 0.2 + 5^2  * 0.2

E(x^2) = 10.5

The standard deviation is:

\sigma = \sqrt{E(x^2) - (E(x))^2}

\sigma = \sqrt{10.5 - 2.7^2}

\sigma = \sqrt{10.5 - 7.29}

\sigma = \sqrt{3.21}

<em></em>\sigma = 1.8<em> --- approximated</em>

5 0
3 years ago
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