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Ahat [919]
3 years ago
11

Translate this formula into an english sentence using this "dictionary":

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

Answer: If the solution's boiling point drops because salt is added to the soltuiton, then the reason the solution boils sooner is the addition of salt to the solution

Step-by-step explanation:

The re are two cause - consequence relations inside an other one.

I use 3 different cause - consequence connectors not to mix them up.

A --> D equals “ D because A “

A --> S equals “ the reason S happens is A “

(A --> D) --> (A --> S) Equals “ if (A --> D) then (A --> S) “

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Can y'all help me with this?
Kazeer [188]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>.</em>

5 0
3 years ago
The half-life of a certain radioactive substance is 45 days. There are 6.2 grams present initially. On what day
kvasek [131]

Answer:

There will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days

Step-by-step explanation:

The given parameters are;

The half life of the radioactive substance = 45 days

The mass of the substance initially present = 6.2 grams

The expression for evaluating the half life is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}

Where;

N(t) = The amount of the substance left after a given time period = 1 gram

N₀ = The initial amount of the radioactive substance = 6.2 grams

t_{1/2} = The half life of the radioactive substance = 45 days

Substituting the values gives;

1 = 6.2 \left (\dfrac{1}{2} \right )^{\dfrac{t}{45}

\dfrac{1}{6.2}  =  \left (\dfrac{1}{2} \right )^{\dfrac{t}{45}

ln\left (\dfrac{1}{6.2} \right )  =  {\dfrac{t}{45} \times ln \left (\dfrac{1}{2} \right )

t = 45 \times \dfrac{ln\left (\dfrac{1}{6.2} \right ) }{ln \left (\dfrac{1}{2} \right )} \approx 118.45 \ days

The time that it takes for the mass of the radioactive substance to remain 1 g ≈ 118.45 days

Therefore, there will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days.

3 0
3 years ago
NEED ANSWER ASAP!!!
ExtremeBDS [4]

Answer:

a=4+2/x <-- 2 over x its a fraction

Step-by-step explanation:

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4 years ago
7233 divided by 164 equals
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7233/164=44.10
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X= a+b+c+bx/a(x-b) but I’m not completely sure
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