Let the number of chemistry books be x and the number of calculus books be y
total number of books in each case is:
x+y=24
x=24-y.....i
Weight of each case:
2707.2/20
=135.36
thus
4.2x+6.0y=135.36..ii substituting i in ii
4.2(24-y)+6y=135.36
100.8-4.2y+6y=135.36
hence
1.8y=34.56
y=19.2
hence
x=24-19.2
x=4.8
thus the number of chemistry books was 4.8*20=96 number of calculus was
19.2*20
=384 books
Answer:
Step-by-step explanation:
(-7 - 1)/(6 + 2) = -8/8 = -1
y - 1 = -1(x + 2)
y - 1 = -x - 2
y = -x - 1
I believe that the answer is B. 3.3 m
Hope that helps
The length of FG would be BC. This is because FG and BC corresponds on the shape letter sequence. This would mean that EF would be AB, that GH would be CD, and that HE would be DA.
$.86 (or more specifically .864)
basically just divide 4.32 by 5 :)
