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Tatiana [17]
3 years ago
10

Is the square root of 8 irrational

Mathematics
2 answers:
shusha [124]3 years ago
4 0

Answer:

The square root of 8 is an irrational number

Step-by-step explanation:


Andru [333]3 years ago
4 0

Answer and Explanation :

The square root of 8, or √(8), is 2√(2).

The square root of a number a is a number that when multiplied by itself gives a. In other words, √(a) = b if b × b = a.

If we plug √(8) into our calculator, we will get a very long decimal that is rounded to a specific decimal place, so it is not an exact answer.  

√(8) ≈ 2.8284271247...

This is because √(8) is an irrational number. When this is the case, we can find an exact answer of √(a), where a is not a perfect square, by simplifying the square root. To do this, we use the following steps and rules:

If possible, rewrite a as a product of a perfect square and another number. If this is not possible, then the square root is as simplified as possible.

Break the square root up using the rule that √(a × b) = √(a) × √(b).

Evaluate the square root that is a perfect square.

Repeat the entire process for the square root that is not a perfect square until it cannot be simplified any further.

Therefore, to simplify √(8), we first rewrite 8 as a product of a perfect square and another number. The number 4 is a perfect square and a factor of 8, so we can rewrite 8 as 4 × 2:

√(8) = √(4 × 2)

We now use our rule to break up the square root:

√(4 × 2) = √(4) × √(2)

Now we evaluate √(4) as 2 (because 2 × 2 = 4):

√(4) × √(2) = 2 × √(2) = 2√(2)

Because 2 doesn't have any perfect square factors, √(2) is as simplified as possible. Therefore, √(8) is equal to 2√(2).

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