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larisa [96]
3 years ago
10

Ebony's gross income is $46 660 with allowable tax deductions of $4120. a What is Ebony's taxable income? b Calculate the amount

of tax due. c Ebony has paid $95 per week in tax. How much does Ebony owe in tax?

Mathematics
1 answer:
jasenka [17]3 years ago
3 0

Answer:

(a) Ebony's taxable income = $42,540

(b) Amount of tax due = $5190.3

(c) Amount of tax owed = $4810.3

Step-by-step explanation:

Ebony's gross income = $46,660 (given)

Allowable tax deductions = $4,120 (given)

(a) Taxable Income = Gross income - Tax deductions

Ebony's taxable income = $46,660 - $4,120

Ebony's taxable income = $42,540

(b) Amount of tax due = 22% of Taxable Income,

Refer to the USA Tax Brackets for 2019 (See Attached image)

Amount of tax due = 10% on first $9,700 + 12% on ($39475-$9700) + 22% on  ($42540-$39475).

Amount of tax due = 10% on first $9,700 + 12% on $29775 + 22% on $3065.

Amount of tax due = $970 + $3573 + $647.3

Amount of tax due = $5190.3

(c) Ebony pays $95 per week in tax. In four weeks (a month), she'd pay

$95 * 4 = $380

Amount of tax owed = Amount of tax due - Amount of tax paid

Amount of tax owed = $5190.3 - $380 = $4810.3

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Answer:

BC=11\ cm

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

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substitute the values

60\°=\frac{1}{2}[arc\ DC]

120\°=arc\ DC

arc\ DC=120\°

step 2

Find the measure of arc BC

we know that

arc\ DC+arc\ BC=180\° ----> because the diameter BD divide the circle into two equal parts

120\°+arc\ BC=180\°

arc\ BC=180\°-120\°=60\°

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

m\angle BDC=\frac{1}{2}[arc\ BC]

substitute the values

m\angle BDC=\frac{1}{2}[60\°]

m\angle BDC=30\°

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

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sin(\angle BDC)=BC/BD

BC=(BD)sin(\angle BDC)

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6 0
3 years ago
Please answer question three and four if you can :)<br> Show full working out ty;)
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Step-by-step explanation:

3

Let D be the mid point of side BC, [B(2, - 1), C(5, 2)].

Therefore, by mid-point formula:

D = ( \frac{2 + 5}{2},  \:  \:  \frac{ - 1 + 2}{2} ) = ( \frac{7}{2}, \:  \:  \frac{ 1}{2} ) \\ \therefore D= (3.5, \:  \: 0.5) \\  \& \: A=(-1,\:\:4)...(given) \\\\  now \: by \: distance \: formula \\  \\ Length  \: of \:  segment  \: AD \\  =  \sqrt{( - 1 - 3.5)^{2}  +  {(4 - 0.5)}^{2} }  \\ =  \sqrt{(4.5)^{2}  +  {(3.5)}^{2} }  \\ =  \sqrt{20.25 + 12.25 }  \\  =  \sqrt{32.5}  \\    \red{ \boxed{\therefore Length  \: of \:  segment  \: AD  = 5.7 \: units}}

4 (a)

Equation of line AB[A(2, 1), B(-2, - 11)] in two point form is given as:

\frac{y-y_1}{y_1-y_2} =\frac{x-x_1}{x_1 - x_2} \\\\\therefore \frac{y-1}{1-(-11)} =\frac{x-2}{2 - (-2) } \\\\\therefore \frac{y-1}{1+11} =\frac{x-2}{2 +2} \\\\\therefore \frac{y-1}{12} =\frac{x-2}{4} \\\\\therefore \frac{y-1}{3} =\frac{x-2}{1} \\\\\therefore y-1= 3(x - 2)\\\\\therefore y= 3x - 6+1\\\\\therefore y= 3x - 5\\\\ \huge \purple {\boxed {\therefore 3x - y-5=0}} \\

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Now we have to check whether C(4, 7) lie on line AB or not.

Let us substitute x = 4 & y = 7 on the Left hand side of equation of line AB and if it gives us 0, then C lies on the line.

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Hence, point C (4, 7) lie on the straight line AB.

4(b)

Like we did in 4(a), first find the equation of line AB and then substitute the coordinates of point C in equation and if they satisfy the equation, then all the three points lie on the straight line.

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