Answer:
Step-by-step explanation:
Let many universities and colleges have conducted supplemental instruction(SI) programs. In that a student facilitator he meets the students group regularly who are enrolled in the course to promote discussion of course material and enhance subject mastery.
Here the students in a large statistics group are classified into two groups:
1). Control group: This group will not participate in SI and
2). Treatment group: This group will participate in SI.
a)Suppose they are samples from an existing population, Then it would be the population of students who are taking the course in question and who had supplemental instruction. And this would be same as the sample. Here we can guess that this is a conceptual population - The students who might take the class and get SI.
b)Some students might be more motivated, and they might spend the extra time in the SI sessions and do better. Here they have done better anyway because of their motivation. There is other possibility that some students have weak background and know it and take the exam, But still do not do as well as the others. Here we cannot separate out the effect of the SI from a lot of possibilities if you allow students to choose.
The random assignment guarantees ‘Unbiased’ results - good students and bad are just as likely to get the SI or control.
c)There wouldn't be any basis for comparison otherwise.
Answer:
yg yc8ggt 8tycg6ctg7t6gt
Step-by-step explanation:
gygc86gc688rc6iycrgciutv
So really all you have to do is simply the expressions on top to match them.
Starting with (4t-8/5)-(3-4/3t), distribute the negative sign to the right portion in parentheses, then distribute it all out and you will get 16/3t- 23/5
Basically, use distribution to simplify, here's all the matches:
(4t-8/5)-(3-4/3t) --> 16/3t- 23/5
5(2t+1)+(-7t+28) --> 3t+33
(-9/2t+3)+(7/4t+33) --> -11/4t+36
3(3t-4)-(2t+10) --> 7t-22
Answer:
Step-by-step explanation:
Given
Required
Determine how much goats in field A, get.
To do this, we simply multiply the percentage feed received by goats in field A by the actual bags of feeds
i.e.
Convert percentage to decimal
<em>Hence, goats in field A get 11.76kg of feeds</em>
