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natka813 [3]
3 years ago
8

Please help asap!!!! 53 points!

Mathematics
2 answers:
AfilCa [17]3 years ago
8 0
The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.
The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:
(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.
So one form of the equation would be:
y = -1x - 2
Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)
and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3
so we get: y-k = -1 (x--5)...
y-3 = -(x+5)... therefore D) is the correct answer:
expeople1 [14]3 years ago
7 0

Answer:

The easiest way is to graph it based upon the slope (m) and y-intercept (b), in the standard slope-intercept form: y = m (x) + b.

The line above intercepts the y-axis at y = -2, which is b. The slope (m) = rise/run = (y2-y1)/(x2-x1 ); so for the point (-4, 2) to (-6, 4) is:

(4-2)/(-6--4) = 2/(-6+4) = 2/-2 = -1.

So one form of the equation would be:

y = -1x - 2

Now the other form of an equation is point-slope: y-k = m (x-h), where the point is at (h, k)

and if we pick -5 for x (bc 5 it listed in 3 of the answers), the y at x=-5 looks like around +3

so we get: y-k = -1 (x--5)...

y-3 = -(x+5)... therefore D) is the correct answer:

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m_a_m_a [10]
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A) We know the domain(x values) is between -10 to infinity
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B) We know the range(y values) is between -6 to infinity
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E) It tells us that f(x) (y) is decreasing between the x values (-6,-2) or between (2,4)

F) Tells us that f(x) (y) is greater than or equal to between the x values of [-8,-4] or between the x values [0, to infinity) so this lets us know our drawing is going to be above or equal to 0 when we are in the values [-8,-4] or [0, to infinity)

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The picture is what the function could look like. It can be different but needs to following the rules that are given 




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<span>f(x) = 2(3x)
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Exponential growth formula.
</span>y=a(1+r)^{x}
<span>a represents the initial value.</span>
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