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goldfiish [28.3K]
3 years ago
12

I don’t know how to set this up

Mathematics
1 answer:
vichka [17]3 years ago
8 0
Let me explain this the best I can. We're missing point T but we know that S is the mid-point between R and T
The distance across from is -9 -2 = -11  and the distance in height is 4-(-1) = 5
Point T will be the same distance from point A is point R (this is getting complicated)
Since point T will be in the opposite direction as point R you'll have to do +11 and -5 instead of -11 and +5...
So to find T, add 11 across and 5 down to point S(2, -1) and you get:
T = (13, -6)
You can draw it out if it makes more sense!
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PLZ HELP DUE AT 12
aleksandrvk [35]

Answer:

The first one would be m^30n^20p^30  

And the second one would be a^2 / d^4  

Step-by-step explanation:

For 1, you have to multiply the inner exponents by the outer one so you get (m^12n^8) times (m^18n^12p^30). Then you mutiply the two together, so you add the exponents, where you get m^30n^20p^30.

For 2, since you're dividing, you have to subtract the exponents so you get a^2d^-4, but since you shouldn't have the negative you turn it into a^2 / d^4

Hope this helps :)

4 0
3 years ago
Solve the system of equations by using substitution.​
katrin [286]

Answer:

(x,y) = (-1,1)

Step-by-step explanation:

Given the equations

y = 2x + 3

x - y = -2

substitute the value of y in the first equation into the second

x - (2x + 3) = -2

x -2x - 3 = -2

-x - 3 = -2

add 3 to both sides

-x = -2 + 3

- x = 1

Divide both sides by -1

x = -1

Substitute into the first equation

y = 2(-1) + 3

y = -2 + 3

y = 1

8 0
3 years ago
Explain why the x-coordinates of the points where the graphs of the equations y = 2−x and y = 8x+4 intersect are the solutions o
Luda [366]
Part 1)
We have two lines:  y = 2-x   and   y = 8x+4
Given two simultaneous equations that are both required to be true.
the solution is the points where the lines cross
Which is where the two equations are equal
Thus the solution that works for both equations is when
2-x = 8x+4
because
where that is true is where the two lines will cross and that is the common point that satisfies both equations.

Part 2) Make tables to find the solution to 2−x = 8x+4. take the integer values of x between −3 and 3

see the attached table
The table shows that none of the integers from [-3,3] work because in no case does
<span>2-x = 8x+4
</span>
To find the solution we need to rearrange the equation to the form x=n
2-x =8x+4
8x+x=2-4
9x=-2
x=-2/9

 The only point that satisfies both equations is
where
 x = -2/9
Find y:
   y = 2-x  = 2 - (-2/9) = 2 + 2/9 = 20/9
Verify we get the same in the other equation
y = 8x+4   =  8(-2/9) + 4 = 20/9 
Thus the only actual solution, being the point where the lines cross,
 is the point (-2/9, 20/9)------> (-0.22,2.22)

Part 3) how can you solve the equation 2−x = 8x+4 graphically?
<span>The point on the graph where the lines cross is the solution to the system of equations
</span>
using a graph tool
see the attached figure

the solution is the point (-0.22,2.22)

4 0
3 years ago
What is the sum of all integers x that satisfy 1 &lt; (pi -1 )x &lt; 10?
DedPeter [7]

Answer:

10

Step-by-step explanation:

pi is 3.14...

pi - 1 is 2.14...

question becomes 1<2.14x and 2.14x < 10

1/2.14 < x, 0.46... < x

x < 10/2.14, x < 4.67...

combining

0.46< x < 4.67

x can be 1, 2, 3, 4

3 0
3 years ago
Read 2 more answers
Consider a graph of the equation and -3x + 4. What is the y-intercept?
Andreas93 [3]

Answer:0,4

Step-by-step explanation: are there multiple choice answers because I wasn’t to make sure this answer is correct

3 0
3 years ago
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