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aivan3 [116]
3 years ago
15

What is the sum of the measures of ∠1 and ∠2? What is the sum of the measures of ∠1 and ∠2?

Mathematics
1 answer:
Tpy6a [65]3 years ago
6 0
The answer is 131. Angle 1= 57, angle 2= 74. 
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If Rs.1760 is left after paying an income tax at the rate of 12%, find the income.​
GREYUIT [131]

Answer:

295/2

Step-by-step explanation:

1760/12

885/6

295/2

7 0
2 years ago
Complete the proof.
trasher [3.6K]
You circle the points on both sides and then you calculate them and get what you need...
5 0
3 years ago
A gas company charges $0.4544 for each therm used. A home used 39.3 therms in a month. How much will the gas company charge that
podryga [215]

Answer:

$17.85792

Step-by-step explanation:

$0.4544 x 39.3 = $17.85792

7 0
2 years ago
verify that the fucntion satisfies the three hypotheses of rolles theorem on the given interval . then find all numbers c that s
Ghella [55]

The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:

<span><span>x1 </span>= 0.42801</span>

<span><span>x2 </span>= −1.51414</span>

<span><span>x3 </span>= 3.08613</span>


x1 and x2 are in the desired interval [-2, 2]

f'(x) = 3x^2 - 4x - 4

so we have:

3x^2 - 4x - 4 = 0

<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6

x_1 = -4/6 = -0.66

x_ 2 = 2

According to Rolle's theorem, we have one point in between:

x1 = 0.42801 and x2 = −1.51414

where f'(x) = 0, and that is <span>x_1 = -0.66</span>

so we see that Rolle's theorem holds in our function.

4 0
3 years ago
What is the distance rounded to the nearest tenth between the points (2 -2) and (6 3)
kotegsom [21]

Answer:

The distance between the points is approximately 6.4

Step-by-step explanation:

The given coordinates of the points are;

(2, -2), and (6, 3)

The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Substituting the known 'x', and 'y', values for the coordinates of the points, we have;

l_{(2, \, -2), \ (6, \, 3) } = \sqrt{\left (3-(-2)  \right )^{2}+\left (6-2  \right )^{2}} = \sqrt{5^2 + 4^2} = \sqrt{41}

Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.

4 0
3 years ago
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