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3 years ago

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use the points a(2, 3) and b(2, −5). complete the description of segment ab and find its length. then describe the image of segm

ent ab under the transformation (x, y) to (x, 2y). and describe the image of segment ab under the transformation (x, y) to (x + 2, y).

1 answer:

Bess [88]3 years ago

8 0

Answer:

2.3

Step-by-step explanation:

idk

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I need help on this question

Alika [10]

Answer:

d

Step-by-step explanation:

8 0

3 years ago

What is the surface area of the pyramid formed from the net shown here? The triangles are equilateral, and each triangle has a h

azamat

Answer:

62.4 square centimeters

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The surface area of the triangular pyramid is equal to the area of the triangular base plus the area of its three lateral triangular faces

In this problem the triangles are equilateral, that means, the

surface area is equal to the area of four congruent equilateral triangles

so

$A=4[\frac{1}{2}(b)(h)]$

we have

$b=6\ cm\\h=5.2\ cm$

substitute

$A=4[\frac{1}{2}(6)(5.2)]=62.4\ cm^2$

3 0

3 years ago

Which table shows a proportional relationship?

Fittoniya [83]

Answer:

I can't understand this that well could you take a picture of the question

5 0

3 years ago

Read 2 more answers

manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

3 years ago

BRAINLIEST to correct answer!!

Len [333]

They are equally spaced so all the circles share the same center point.

4 0

2 years ago

Read 2 more answers