9514 1404 393
Answer:
- Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
- Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E
Step-by-step explanation:
The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.
The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.
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<em>Additional comment</em>
The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.
What are you looking for?
Answer:
b)
a)
a)
Step-by-step explanation:
hope this helps i havent done this in a while
The first A because once you plug in the numbers into the x,y it is easier to find the solution.
The answer for this question is 8
