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3 years ago

Solve for y.

Mathematics

1 answer:

den301095 [7]3 years ago

7 0

Answer by Mimiwhatsup:

$\mathrm{Switch\:sides}\\5x+5y=d\\\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}\\5x+5y-5x=d-5x\\Simplify\\5y=d-5x\\\mathrm{Divide\:both\:sides\:by\:}5\\\frac{5y}{5}=\frac{d}{5}-\frac{5x}{5}\\\mathrm{Simplify}\\y=\frac{d-5x}{5}$

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Josh estimates the height of his desk.what is a reasonable estimate?

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Well it depends on how smart he is

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KIM [24]

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3 years ago

A manufacturer needs to pay $300 to start making a certain new product. Besides the initial costs of $300, this product will als

maw [93]

Answer:

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<u>Average Cost</u>

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3 years ago

If you want to buy an item in a store that costs $32.50 and is on sale for 30% off, then how much would the item actually cost y

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Answer:

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3 years ago

ITS VERY IMPORTANT PLEASE SOLVE THIS

kvv77 [185]

Answer:

$I'm \: assuming \: you \: meant \: "group." \: Draw \: your \: 3 \: circles \: for \: apples, \: bananas, \: and \: cherries \: with \: overlap \: of \: all \: three \: with \: each \: other \: and \: make \: sure \: there \: is \: overlap \: between \: each \: two \: circles \: as \: well. \: Note \: your \: total = 38 + 42 + 14 = 94 \: (necessary \: to \: calculate \: the \: probability) \: is \: greater \: than \: the \: 80 \: people \: surveyed. \: Unfortunately, \: I \: cannot \: draw \: it \: here \: for \: you. \: There \: does \: appear \: to \: be \: a \: problem \: with \: the \: total \: number \: of \: those \: who \: like \: cherries, \: as \: well. \: It \: can't \: be \: 14 \: with \: the \: overlap \: with \: other \: fruit \: likes, \: so \: check \: the \: number \: again. \: Even \: if \: I \: were \: to \: assume \: the \: 6 \: that \: like \: all \: 3 \: fruits \: included \: , for \: example, \: those \: that \: like \: apples \: and \: bananas \: (meaning \: those \: that \: strictly \: like \: apples \: and \: bananas \: = 20 - 6 = 14), \: my \: total \: using \: this \: approach \: would \: be \: 64, \: not \: 80. \: After \: verifying \: the \: question, \: to \: find \: those \: that \: simply \: like \: one \: fruit, \: subtract \: the \: numbers \: that \: overlap \: from \: the \: total \: (using \: your \: original \: data, \: you \: should \: get \: 6 \: people \: like \: only \: apples, \: and \: 6 \: like \: only \: bananas). \: So \: the \: probability \: of \: those \: who \: like \: either \: apples \: or \: bananas \: would \: be \: 6 + 6 / 94 (or 12 / 94) if \: the \: numbers \: were \: correct \: for \: the \: cherry \: fans.$

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3 years ago