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Sveta_85 [38]
4 years ago
5

Let f(x) = x2 − 2x + 2 and g(x) = x − 3. Find f(x) ⋅ g(x). x3 − 6x2 + 12x − 6 x3 − 5x2 + 8x − 6 x3 − 3x2 + 6x − 6 x3 − 2x2 + 5x

− 6
Mathematics
2 answers:
Vika [28.1K]4 years ago
8 0

Answer: Option 2 is correct

x^3-5x^2+8x-6

Explanation:

We have been given two functions f(x)=x^2-2x+2 \\\\and\\g(x)=x-3

we need to find f(x).g(x)  

We need to multiply the given two functions

So, as to multiply (x^2-2x+2)(x-3)

Multiply each term of f(x) with g(x) we will get

x^2(x-3)=x^3-3x^2

-2x(x-3)=-2x^2+6x

2(x-3)=2x-6

Hence the final result after multiplying both the functions is

x^3-5x^2+8x-6

kow [346]4 years ago
3 0
f(x) = x2 - 2x + 2
g(x) = x - 3

(f • g)(x) = (x2 - 2x + 2)(x - 3)
(f • g)(x) = x2(x - 3) - 2x(x - 3) + 2(x - 3)
(f • g)(x) = x3 - 3x2 - 2x2 + 6x + 2x - 6
(f • g)(x) = x3 - 5x2 + 8x - 6

The answer is B.
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Answer: The point (-10,-20) becomes (-8,-16) & point (15,25) becomes (12,20).

Step-by-step explanation:

When a point (x,y) is dilated by a scale factor k from the origin, then the new points become

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The given rule of dilation : (x,y) →(0.8x, 0.8y)

The first point is (-10,-20), so its image will be

(-10,-20)\to (0.8\times-10,0.8\times-20)=(-8,-16)

So, the point (-10,-20)  becomes (-8,-16).

The second point is (15,25), so its image will be

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This is a way to factoring trinomials (there exist different equivalent methods).

Multiply the trinomial but the term accompanying  c^2. This is the second line. Then, you could take the square of the 4c^2, ant try to create a factor () () that will correspond to the expression in the second line. That is, we want 4c^2 + 13(2) c + 42 = (2c + ?) (2c + ?)

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