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kiruha [24]
3 years ago
7

Simplify each problem and expre 1) (2 x 10°) + (5 x 109)

Mathematics
1 answer:
elixir [45]3 years ago
3 0

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

(2 · 10⁰) + (5 · 109)

= (2 · 0) + (5 · 109)

=    2     + (5 · 109)

=    2     +    545

=         547

Your answer is 547.

<em>I hope this helps!</em>

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This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
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L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)

L_x=10+10\lambda x=0\implies1+\lambda x=0

L_y=10+10\lambda y=0\implies1+\lambda y=0

L_z=2+4\lambda z=0\implies1+2\lambda z=0

L_\lambda=5x^2+5y^2+2z^2-42=0

\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z

5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1

z^2=1\implies z=\pm1\implies x=y=\pm2

There are two critical points, at which we have

f\left(2,2,1\right)=42\text{ (a maximum value)}

f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}

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ASAP!!! WILL GIVE BRAINLY!
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Answer:

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Step-by-step explanation:

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