Compare the areas of the 2 different pieces of paper.
For the circle, the area is A=pi * r^2, which works out to A = pi(5 inches)^2.
For the square, the area is A = s^2, where is the side length, which here is 11 inches.
Finish these calculations, and then compare your two areas. Which is the larger?
Answer:
13. B. 24 cm²
14. y = 5⅝ (none of the options is correct)
Step-by-step explanation:
13. The figure is a trapezoid
Area of the trapezoid = ½(a + b)h
Where,
a = 3 cm
b = 5 cm
h = 6 cm
Area = ½(3 + 5)6
= ½(8)6
= 4*6
= 24 cm²
14. Area of the triangle = ½*b*h
The area is given to be 45 cm²
base (b) = 16 cm
height (h) = y
Plug in the values and solve for y
45 = ½*16*y
45 = 8y
Divide both sides by 8
45/8 = 8y/8
45/8 = y
5⅝ = y
y = 5⅝ (none of the options is correct)
Answer:
x=4 y=1 or (4,1)
Step-by-step explanation:
y-intercept: Let x = 0 and solve for y:
(x-1)^2 + (y-2)^2 = 10 => (-1)^2 + y^2 - 4y + 4) = 10
=> 1 + y^2 - 4y + 4 = 10, or y^2 - 4y -5 = 0
The solutions of this quadratic are y = 5 and y = -1.
Thus, the y-intercepts are (0, 5) and (0, -1).
Now find the x-intercepts: Let y = 0 and solve the resulting equation for x:
(x-1)^2 = 10 - (-2)^2, or (x-1)^2 = 10 - 4 = 6.
Taking the sqrt of both sides, x - 1 = plus or minus sqrt(6), or:
x = 1 +√6 and x = 1 - √6, so that the x-intercepts
are (1+√6, 0) and (1-√6, 0).
Substitute all values for x and y into their placement
y<1-6x
(1)<1-6(-1)
1<7
The coordinate pair is (-1,1)
