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geniusboy [140]
3 years ago
8

. Anne is pushing a wheelbarrow filled with mulch to place in her garden. She is pushing the wheelbarrow with a force of 70 N at

an angle of 50° with the horizontal. How much work in joules is Anne doing when she pushes the wheelbarrow 25 meters?
Mathematics
1 answer:
Kruka [31]3 years ago
4 0

<u>Answer:</u>

When Anne pushes the wheelbarrow 25 meters the work done is 1120 joules

<u>Solution:</u>

We know \text { Work }(\mathrm{W})=\text { Force }(\mathrm{F})\times\text { Distance (D) }

Anne is pushing the wheelbarrow with a force of 70 N at an angle of 50^{\circ} with the horizontal

So the force of Anne will be F=70 \cos 50^{\circ}=(70 \times 0.64)=44.8 \mathrm{N}

She pushes the wheelbarrow 25 meter, So D = 25 meters

So, the work,F\times D=(44.8 \times 25)=1120 \text { Joules }

Anne has done total 1120 joules work.

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Answer:

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Step-by-step explanation:

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Where:

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angle EFG and angle GFH are a linear pair, m angle GFH= 2n+38 and m angle GFH=2n+38. what are m angle EFG and m angle GFH
motikmotik

Answer:

Part 1) m∠EFG=94°

Part 2) m∠GFH=86°

Step-by-step explanation:

we know that

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(3n+22)°+(2n+38)°=180°

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<em>Find the measure of angle EFG</em>

m∠EFG=3n+22

substitute the value of n

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<em>Find the measure of angle GFH</em>

m∠GFH=2n+38

substitute the value of n

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{ a }^{ \frac { m }{ n }  }\\ \\ =\sqrt [ n ]{ { a }^{ m } }

Remember that:

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