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anyanavicka [17]
3 years ago
12

Solve for X and check the solution.-2x=4x+9

Mathematics
1 answer:
koban [17]3 years ago
4 0
-2x=4x+9 |-4x
-6x=9 |:(-6)
x=-1,5


Check:

-2*-1,5=4*-1,5+9
3=-6+9
3=3
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Need help ASAP!! I'll give brainliest to whoever answers correctly!!!
jolli1 [7]

Answer:

SRT

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6 0
3 years ago
At a new exhibit in the Museum of Science, people are asked to choose between 94 or 220 random draws from a machine. The machine
Tresset [83]

Answer:

0.0869 = 8.69% probability of getting more than 61% green balls.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The machine is known to have 99 green balls and 78 red balls.

This means that p = \frac{99}{99+78} = 0.5593

Mean and standard deviation:

\mu = p = 0.5593

s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.5593*0.4407}{99+78}} = 0.0373

a. Calculate the probability of getting more than 61% green balls.

This is 1 subtracted by the pvalue of Z when X = 0.61. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.61 - 0.5593}{0.0373}

Z = 1.36

Z = 1.36 has a pvalue of 0.9131

1 - 0.9131 = 0.0869

0.0869 = 8.69% probability of getting more than 61% green balls.

8 0
3 years ago
Explain how to simplify this complex fraction. 330pages/3/4hour.
meriva
Answer:
= 330/1 ÷ 3/4

= (330 × 4) / (3 × 1)

= 1320/3

= 440/1

<span>= 440 

Hope this helps! </span>
7 0
3 years ago
The campsite is square in shape and has a length of 65 metres.<br> What is the area of the campsite?
IgorLugansk [536]
65x65=4225
that's your answer (4225)
4 0
3 years ago
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Tickets for the basketball game cost 14$ each. If the sale of the tickets brought in 2,212$, how many tickets were sold?
rosijanka [135]
15.78 is the answer to the qustion that you have asked.
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