You will choose 1 cheese 3 different ways because there are three types of cheeses.

You will choose your topings 6 different ways. 4!/(2!2!) = 4*3/2 = 6

Therefore you will be able to get 6 * 3 different pizzas = 18 pizza combinations.

To confirm the toppings, suppose they are (M)ushrooms (P)epperoni (O)nions and (B)acon

M P
M O
M B
P O
P B
O B

Total 6.The order doesn't matter here. M O is the same thing as OM

8 0

3 years ago

Find the inverse of 2∛(x+2)

Artemon [7]

$y=2\sqrt[3]{x+2}\ \ \ |divide\ both\ sides\ by\ 2\\\\\sqrt[3]{x+2}=\dfrac{y}{2}\to x+2=\left(\frac{y}{2}\right)^3\ \ \ |subtract\ 2\ from\ both\ sides\\\\x=\dfrac{y^3}{2^3}-2\\\\x=\dfrac{1}{8}y^3-2\\\\\boxed{f(x)=2\sqrt[3]{x+2}\to f^{-1}(x)=\frac{1}{8}y^3-2}$

5 0

3 years ago

Square one factor from column A and add it to one factor from column B to develop your own identity. (image attached) 60 points

Tamiku [17]

Answer:

x^4+64 = x^2 -4x+8 * x^2 +4x+8

Step-by-step explanation:

6 0

2 years ago