Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
9 5/6 - 2 1/3 is 7 1/2.
You could get this answer by finding the same denominator of the fractions. The LCM of both is 6. Multiply the 1 of the second fraction 2 times because you had to multiply the denominator 2 times to get to 6.
You should have 2 2/6.
Now get 9 5/6 - 2 2/6.
The answer is 7 3/6, simplifies into 7 1/2.
9 5/6 - 2 1/3 is 7 1/2.
<span>6x+7=6
Subtract both sides by 7
</span>6x+7-7=6-7
6x=-1
Divide both sides by 6 to isolate x
6x/6=-1/6
x=-1/6
Since it starts at 50 and goes to 35....it is a decrease since the amount is going down, or getting smaller. To find the percent, first find the difference 50-35 = 15; then divide by the initial amount of 50. So, 15/50 = 0.3, and then convert that to a percent by multiplying by 100. Therefore the percent decrease is 30%
Answer:
idek
Step-by-step explanation:
idek