All categories

1 year ago

Does anyone know how to do this

Mathematics

1 answer:

otez555 [7]1 year ago

8 0

Considering the area of the rectangle, we have that the length is of 8 units and the width is of 10 units.

<h3>What is the area of a rectangle?</h3>

The area of a rectangle of length l and width w is given as follows:

A = lw.

In this problem, the area is of 80 square units, while the length and the width are consecutive even integers, hence:

A = 80.

w = l + 2.

Then:

l(l + 2) = 80

l² + 2l - 80 = 0

(l + 10)(l - 8) = 0.

We need the positive measure, hence:

l - 8= 0 -> l = 8 units.

w = l + 2 = 10 units.

More can be learned about the area of a rectangle at brainly.com/question/10489198

#SPJ1

You might be interested in

7k-10=-8-4(k+6)<br> Helpp

Vilka [71]

Answer:

k=-2

Step-by-step explanation:

7k-10=-8-4(k+6)

7k-10=-8-4k-24

7k-10=-32-4k

11k-10=-32

11k=-22

k=-2

4 0

2 years ago

Read 2 more answers

How to graph f(x)=(x-2)^2+5

tatyana61 [14]

That's a quadratic, a nice parabola in vertex form.

The parabola has a positive x^2 term, so it's a CUP, concave up positive. It will have a minimum at the vertex, which is (2,5). Plot that point.

Now we need a couple of guide points to draw the usual parabola going up from both sides of its vertex. We try x=0 giving (0,9) and see that x=4 also gives 9, (4,9). Plot the parabola through those two points and the vertex and you're done.

3 0

2 years ago

Read 2 more answers

If the height of the rectangle is 12 ft and the area is 72 ft what is the base of the rectangle

xxMikexx [17]

6 ft is the base of the rectangle

5 0

2 years ago

Read 2 more answers

Write a quadratic equation given the roots -1/3 and 5, show your work

Travka [436]

$\boxed{(x - a)(x - b) = 0}$

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

$x = - \frac{1}{3} \\ x = 5$

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

$(x + \frac{1}{3} )(x - 5) = 0$

Here we can convert the expression x+1/3 to this.

$x + \frac{1}{3} = 0 \\ 3x + 1 = 0$

Rewrite the equation.

$(3x + 1)(x - 5) = 0$

Simplify by multiplying both expressions.

$3 {x}^{2} - 15x + x - 5 = 0 \\ 3 {x}^{2} - 14x - 5 = 0$

<u>Answer</u><u> </u><u>Check</u>

Substitute the given roots in the equation.

$3 {(5)}^{2} - 14(5) - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0$

$3( - \frac{1}{3} )^{2} - 14( - \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) + \frac{14}{3} - 5 = 0 \\ \frac{1}{3} + \frac{14}{3} - \frac{15}{3} = 0 \\ \frac{15}{3} - \frac{15}{3} = 0 \\ 0 = 0$