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VLD [36.1K]
4 years ago
5

Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the

distance is 15 cm when the weight is 2 ​kg, what is the distance when the weight is 7 ​kg?
Mathematics
1 answer:
algol [13]4 years ago
8 0

The distance is 52.5 cm when weight is 7kg

Step-by-step explanation:

Distance is 15 cm when weight is 2 kg

We need to find the distance d when weight is 7 kg

Since distance and weight varies directly so,

\frac{15}{2}=\frac{d}{7}

Solving the above expression:

\frac{15}{2}=\frac{d}{7}\\Cross\,\,multiply\\15*7=d*2\\105=d*2\\d=\frac{105}{2}\\d=52.5

So, The distance is 52.5 cm when weight is 7kg

Keywords: Direct relation between two quantities

Learn more about Direct relation between two quantities at:

  • brainly.com/question/10708697
  • brainly.com/question/10717746
  • brainly.com/question/11253316

#learnwithBrainly

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