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Tema [17]
2 years ago
5

4(PX+1)=64 what is the value of x in terms of p and what is the value of x when p is -5 ?

Mathematics
1 answer:
Oksana_A [137]2 years ago
4 0

Answer:

x = -3

Step-by-step explanation:

4(PX+1)=64\\\\p= -5

Substitute -5 for p in the given equation and solve

4(-5(x)+1)=64\\\\\mathrm{Divide\:both\:sides\:by\:}4\\\frac{4\left(-5x+1\right)}{4}=\frac{64}{4}\\\\Simplify\\-5x+1=16\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\-5x+1-1=16-1\\\\Simplify\\-5x =15\\\\\mathrm{Divide\:both\:sides\:by\:}-5\\\frac{-5x}{-5}=\frac{15}{-5}\\\\Simplify\\x = -3

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Answer:

The total number of family members is 21.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of these sets.

I am going to say that:

-The set A represents those that would not go to a park.

-The set B represents those who would not go to a beach.

-The set C represents those who would not go to the family cottage.

The value d represents those who would go to all three places.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a are those that would only not go to a park, A \cap B are those who would not got to a park or to the beach, A \cap C are those who would not go to a park or to the famili cottage. And A \cap B \cap C are those that would not go to any of these places.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following values:

a,b,c,d,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

The total number of family members is the sum of all these values:

T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

We start finding the values from the intersection of the three sets

5 would not go to a park or a beach or to the family​ cottage.

This means that A \cap B \cap C = 5

1 would go to all three places. This means that d = 1.

8 would go to neither a park nor the family​ cottage

This means that:

A \cap C + (A \cap B \cap C) = 8

A \cap C = 3

8 would go to neither a beach nor the family​ cottage

B \cap C + (A \cap B \cap C) = 8

B \cap C = 3

7 would go to neither a park nor a​ beach

A \cap B + (A \cap B \cap C) = 7

A \cap B = 2

15 would not go to the family​ cottage

C = 15

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

15 = c + 3 + 3 + 5

c = 4

12 would not go to a​ beach

B = 12

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

12 = b + 3 + 2 + 5

b = 2

11 would not go to a​ park

A = 11

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

11 = a + 2 + 3 + 5

a = 1

Now, we can find the total number of family members.

T = a + b + c + d + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

T = 1 + 2 + 4 + 1 + 2 + 3 + 3 + 5

T = 21

The total number of family members is 21.

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