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Katyanochek1 [597]
2 years ago
11

Can someone help on this question I’m not sure if I’m correct

Mathematics
2 answers:
MrRa [10]2 years ago
7 0
**You are indeed correct, the answer is 4.**

The degree in a polynomial is the highest exponent of a variable in the function/equation. In this case, there is 3 and 4, and 4 is the highest exponent (the degree).
erik [133]2 years ago
4 0
<h3>Answer: Choice A is correct.</h3>

The degree is the largest exponent of a single variable polynomial.

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Write an expression in simplest form the perimeter of the figure ?
kondor19780726 [428]

Answer:

4+11a+8b

Step-by-step explanation:

1) 4+3a+2b+6b+5a+3a

2) 3a+3a+5a=11a. 2b+6b=8b

5 0
3 years ago
How to compare 10.5 to 11 and 19
Marizza181 [45]

Answer:

Line up the decimal points. **Answer is Least to greatest: 10.5 , 11, 19**

Step-by-step explanation:

You need to line each number up.

10.5

11.0

19.0

The reason why 11 and 19 have a decimal point and zero at the end is because you need to do that in order to compare the numbers.

This problem is also a little common sense because 10.5 is the smallest, 19 is the largest while 11 is in the middle.

4 0
2 years ago
Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )
Zina [86]

Answer:

\purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

Step-by-step explanation:

\cos( \alpha ) =  \frac{ \sqrt{6} }{6}  =  \frac{1}{ \sqrt{6} }  \\  \\  \therefore \:  \sin( \alpha )  =  \sqrt{1 -  { \cos}^{2} ( \alpha ) }  \\  \\  =  \sqrt{1 -  \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} }  \\  \\ =  \sqrt{1 -  {\frac{1}{ {6} }}}  \\  \\ =  \sqrt{ {\frac{6 - 1}{ {6} }}}   \\  \\  \red{\sin( \alpha ) =  \sqrt{ { \frac{5}{ {6} }}} } \\  \\  \tan( \alpha ) =  \frac{\sin( \alpha ) }{\cos( \alpha ) }  =  \sqrt{5}  \\  \\ \sin( \beta )  =  \frac{ \sqrt{2} }{4}  \\  \\  \implies \: \cos( \beta )  =   \sqrt{ \frac{7}{8} }  \\  \\ \tan( \beta )  =  \frac{\sin( \beta ) }{\cos( \beta ) } =  \frac{1}{ \sqrt{7} }   \\  \\  \tan( \alpha  -  \beta ) =  \frac{ \tan \alpha  -  \tan \beta }{1 +  \tan \alpha .  \tan \beta}  \\  \\  =  \frac{ \sqrt{5} -  \frac{1}{ \sqrt{7} }  }{1 +  \sqrt{5} . \frac{1}{ \sqrt{7} } }  \\  \\  =  \frac{ \sqrt{35} - 1 }{ \sqrt{7}  +  \sqrt{5} }  \\  \\  \purple{ \bold{ \tan( \alpha  -  \beta ) = 1.00701798}}

8 0
3 years ago
Select the correct answer.
sergejj [24]
G(x)/f(x) will be simplified to (x+3)(x-3)/2-x^1/2,
which will give you [0,4) ∪(4, ∞).
Choice B
5 0
3 years ago
Write an equation in slope-intercept <br> A slope of 0 and passes through (0,-3)
Finger [1]

If the line has a slope = 0,  then it's a horizontal line

with the equation y = constant.

The line passes through (0, -3) → y= -3

<h3>Answer: y = -3</h3>
6 0
3 years ago
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