Force 1, F1 = 90, angle 30°
Force 2, F2 = 50, angle 160°
F1 = 90 cos(30) i + 90 sin (30) j
F2 = 50 cos (160) i + 50 sin (160) j
F1 = 90*0.866 i + 90*0.5 j
F2 = 50*(- 0.940) i + 50*0.342 j
F1 = 77.94 i + 45 j
F2 = -47 i +17.10 j
Resultant force, Fr = F1 + F2
Fr = [77.94 - 47.00] i +[45 +17.10]j = 30.94 i + 62.10 j
Magnitude = √[30.94 ^2 + 62.10^2] = 69.38 pounds
Direction = arctan[62.10/30.94] = 63.52 °
Answer:
k²+16k+ 153
Step-by-step explanation:
k²+16k+64+89
= k²+16k+ 153
Answer:
DONT KNOW SRY
Step-by-step explanation:
Answer:
Step-by-step explanation:
Since the two triangles are similar, you can use proportions to solve for the value of ![x](https://tex.z-dn.net/?f=x)
![\frac{x}{12} = \frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B12%7D%20%20%3D%20%5Cfrac%7B4%7D%7B3%7D)
Now, just multiply 4 and 12.
![4 * 12 = 48](https://tex.z-dn.net/?f=4%20%2A%2012%20%3D%2048)
Then divide that by 3.
![48 / 3 = 16](https://tex.z-dn.net/?f=48%20%2F%203%20%3D%2016)
Therefore,
.