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DochEvi [55]
3 years ago
8

Consider the all-units quantity discount schedule below. Quantity Ordered Price Per Unit EOQ at that Price 1-499 $300 952 500-99

9 $280 986 1000-1499 $260 1023 1500-1999 $230 1087 2000 and over $200 1166 Which of the following sets of order quantities is guaranteed to contain the optimal solution (i.e., best order quantity)?A. {986, 1023, 1500 B. 1023, 1500, 2000} C. (986, 1000, 1500, 2000) D. {1, 500, 1000, 1500, 2000} E. [952, 986, 1023,1087, 1166]
Business
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer: B. 1023, 1500, 2000}

Explanation:

The Optimal solution should contain the set of quantities that would require the lowest no. of orders to achieve a discount in a class.

1,023 is quite close to the lowest amount required of 1,000 in the 1,000 to 1,499 range.

So are 1,500 and 2,000.

Option D can also work but it has too many order quantities and will inflate the price.

The Optimal Solution therefore has to be from this option.

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AleksandrR [38]

Answer:

the $400 you would have earned if you sold the toy

Explanation:

Opportunity cost or implicit is the cost of the next best option forgone when one alternative is chosen over other alternatives.

If you didn't give the toy to the child, you could have sold it for $400. Selling the toy is the next option and thus, it is the opportunity cost

7 0
3 years ago
Winkle Corporation uses the FIFO method in its process costing system. Beginning inventory in the mixing processing center consi
Mice21 [21]

Answer:

d. 6,700 units

Explanation:

The computation of the equivalent units for conversion cost by using the FIFO method is shown below:

= Beginning inventory units × remaining percentage + units started and completed + ending inventory units × completion percentage

= 5,000 × 10% + (10,000 - 5,000) + 2,000 × 60%

= 500 + 5,000 + 1,200

= 6,700 units

We simply applied the above formula

6 0
3 years ago
Does retail storage with customer pick up pose any risk for distribution network?
sukhopar [10]

Inventory cost is higher than all other options. If there are many small players at the customer stage, each requiring small amount of the product at a time.

4 0
3 years ago
Sale price $60 $100 Variable costs $35 $60 Machine hours required for 1 vase 1 2 Total fixed costs are $600,000, and Rose Incorp
MrRissso [65]

Answer:

a) CM1 = 25

CM2 = 40

b) CMmh1 = 25

CMmh2 = 20

c) 25,000 units of Vase 1 and 12,500 units of Vase 2

d) OI = $ 525,000

Explanation:

a. Determine the contribution margin per unit for each type of vase.

The contribution margin per unit is equal to the difference between the sale price and the variable cost per unit:

CM_1=P_1-VC_1=60-35=25\\\\\\CM_2=P_2-VC_2=100-60=40

b. Determine the contribution margin per machine hour for each type of vase.

For the Vase 1, the number of machine hours per unit is 1. So the contribution margin per machine hour for Vase 1 is equal to CM1=$25.

For the Vase 2, the number of machine hours per unit is 2. Then, the contribution margin per machine hour for Vase 2 is equal to CM2=$40/2=$20.

c. Determine the number of units of each style of vase that Rose Incorporated should produce to maximize operating income.

There are 3 restrictions:

- Max 25,000 units of Vase 1

- Max 25,000 units of Vase 2

- 50,000 hours of machine hour

As the contribution margin per machine hour is higher for the Vase 1, so we start producing the more we can of Vase 1. The limit is 25,000 units.

Then, we are left with 25,000 machine hours available for Vase 2. We can produce 25,000/2=12,500 units, which is under the market constraint.

d. What is the dollar amount of the maximum operating income as calculated in C above

The operating income for the mix proposed in C is:

OI=CM_1*q_1+CM_2*q_2-FC\\\\OI=25*25,000+40*12,500-600,000\\\\OI=625,000+500,000-600,000\\\\OI=525,000

4 0
3 years ago
Xavier is using a query that includes a LIKE comparison operator with the value of A[a-n]*. Which option would match this operat
Lera25 [3.4K]

Answer:

Aaron

Explanation:

3 0
3 years ago
Read 2 more answers
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