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maksim [4K]
3 years ago
12

The Hawks have won 12 games, which is 60% of the games they have played this season.How many games have the Hawks played this se

asons?
Mathematics
2 answers:
loris [4]3 years ago
4 0

Answer:

20 games

Step-by-step explanation:

Let

x ----> total games played this season

we know that

12 games represent 60% of the games they have played this season

so

using proportion

Find out how many games represent a percentage of 100%

\frac{12}{60\%}=\frac{x}{100\%}\\\\x=12(100)/60\\\\x=20\ games

Kryger [21]3 years ago
3 0

Answer:

20 games

Step-by-step explanation:

no

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Solve for r. You must write your answer in fully simplified form.<br> -20 = -15r
nevsk [136]

Answer:

r = 4/3

Step-by-step explanation:

-20 = -15r

Divide both sides by -15.

-20 / -15 = r

The negatives cancel, so

20 / 15 = r

Simplify by taking 5 out of the numerator and denominator. 20/5 = 4, 15/5 = 3.

4 / 3 = r

<u>So r = 4/3.</u>

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2 years ago
4x-6 equals -2 algebraically​
Angelina_Jolie [31]

Answer:

x=1

Step-by-step explanation:

4x-6= -2

    +6=+6

   <u>4x</u>=<u>4</u>

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3 years ago
I’m I right? I kinda but kinda don’t get this question I lost my notes and I just learnt this
belka [17]

Yes, you are correct

3 0
2 years ago
Read 2 more answers
Malcolm bought 6 bowls for $13.20. What is the unit rate
erica [24]
You divide the total amount by the umber of items. 13.20 divided by 6. This is 2.2. The unit rate is 2.2 dollars
5 0
2 years ago
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If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf
jonny [76]
With the curve C parameterized by

C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k

with 0\le t\le\dfrac\pi2, and given the vector field

\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k

the work done by \mathbf f on a particle moving on along C is given by the line integral

\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt

where

\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt

The integral is then

\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt
=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t
=269
6 0
3 years ago
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